B. Are the necessary conditions present to carry out this inference procedure? Explain in context.No. The sample is not large enough and the histogram is uniform.O Our sample was not larger than 30 in size, but a histogram has a reasonably symmetric bellshape. It is stated that the sample was randomly gathered.Carry out the procedure ("crunch the numbers"):C. Sample mean (rounded to 3 decimal places proeprly):D. Standard deviation of the sample (rounded to 3 decimal places proeprly): s =E. Test statistic (rounded to 4 decimal places proeprly): tF. P-value (rounded to 4 decimal places proeprly):G. Decision:TODDLERFail to reject the null hypothesis.Reject the null hypothesis.H. Write a conclusion in context.PRETETTBecause our p-value is not less than our level of significance (alpha=0.05), we do not havesufficient evidence to reject the null hypothesis. We cannot conclude that the overall meanlawn length is higher than 3.5 inches.Because our p-value is less than our level of significance (alpha=0.05), we have sufficientevidence to reject the null hypothesis. The evidence seems to indicate that the overall meanlawn lengthis higher than 3.5 inches. 5torProctorio Practice...Testing a claim about a population mean: t-TestAn overly involved "neighborhood watch" group has been investigating the length of lawns. In years past,lawns had been mowed to a mean length of 3.5 inches._id=325/118A recent random sample of lawn lengths is given below. Conduct an appropriate test, at a 5% significancelevel, to determine if the overall mean lawn length is now higher than 3.5 inches.Data (lawn lengths, measured in inches):3.47 4.13 3.52 3.06 4.36 3.91 3.68 3.684.38 4.16 2.98 4.84 3.98 4.07 2.864.672.67 3.88 4.03 2.63Checksum: 74.96Click Download CSV to download csv file of data or copy/paste the data into Excel. After downloading thefile, you may want to save it as an Excel Workbook.A. Consider the parameter of interest and choose the correct alternative hypothesis.μ< 3.50μ 73.5Ou 3.5Ομ < 3.5Ο μ > 3.5μ = 3.5B. Are the necessary conditions present to carry out this inference procedure? Explain in context.No. The sample is not large enough and the histogram is uniform.Our sample was not larger than 30 in size, but a histogram has a reasonably symmetric bellshape. It is stated that the sample was randomly gathered.Carry out the procedure ("crunch the numbers"):C. Sample mean (rounded to 3 decimal places proeprly): x =

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MATLAB: An Introduction with Applications

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Author:Amos Gilat

Publisher:Amos Gilat

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Where are the deer? Random samples of square-kilometer plots were taken in different ecological locations of a national park. The deer counts per square kilometer were recorded and are shown in the following table. Mountain Brush Sagebrush Grassland Pinon Juniper 35 17 2 30 53 6 20 19 2 26 19 8 Shall we reject or accept the claim that there is no difference in the mean number of deer per square kilometer in these different ecological locations? Use a 5% level of significance. (a) What is the level of significance? State the null and alternate hypotheses. Ho: μ1 = μ2 = μ3; H1: All three means are different.Ho: μ1 = μ2 = μ3; H1: Exactly two means are equal. Ho: μ1 = μ2 = μ3; H1: Not all the means are equal.Ho: μ1 = μ2 = μ3; H1: At least two means are equal. (b) Find SSTOT, SSBET, and SSW and check that SSTOT = SSBET + SSW. (Use 3 decimal places.) SSTOT = SSBET = SSW = Find d.f.BET, d.f.W, MSBET, and MSW. (Use 2 decimal places for MSBET, and MSW.)…
A developmental psychologist is interested in studying how long babies gaze at a photograph of a human face. To test this question, she shows a picture to a sample of six babies and records the length of their gaze in seconds. The data are as follows: 12, 17, 18, 20, 20, 29. Calculate the mean, median, mode, range, variance and standard deviation for the sample.
The height of women ages 20-29 is normally distributed, with a mean of 63.8 inches. Assume o = 2.8 inches. Are you more likely to randomly select 1 woman with a height less than 65.2 inches or are you more likely to select a sample of 23 women with a mean height less than 65.2 inches? Explain. Click the icon to view page 1 of the standard normal table. Click the icon to view page 2 of the standard normal table. What is the probability of randomly selecting 1 woman with a height less than 65.2 inches? (Round to four decimal places as needed.)
A marketing research consultant interested in determining the proportion of customers who use online dating services. A random sample of 2001 people were asked and the count revealed that 15% used online dating services. Data 10 Samples Generate 100 Samples Generate 1000 Samples Reset Plot portion- ht Tail samples - do00 mean- o, 150 std. error=0,008O 0.025 0.950 0.025 0.130 o135 o50 0.16 0.140 0.145 0.155 0.160 0.170 0.175 0.15 0.134 0.166 Compute a 95% confidence interval for the true proportion of people who use online dating. 95% Confidence interval What is the numerical value of the margin of error? If the researcher is using a confidence level of 95% what percent of confidence intervals would not capture the true parameter?
An air condition company will spend an average of 64 minutes with a standard deviation of 19 minutes on a service call. Based on this, and assuming a normal distribution, 5% of service calls will take more than how much time to complete? Approximately 66.29 minutes O Approximately 32.75 minutes O Approximately 39.41 minutes O Approximately 95.25 minutes O Approximately 77.23 minutes
A criminologist rode along with patrol officers for several weeks and recorded the number of minutes police officers spent interviewing witness at a variety of crime scenes. Using data collected on a group of 35 patrol officers, she observes an average interviewing time of 307 minutes. Assume that the population standard deviation a is estimated to be 83 minutes. What is the point estimate for the population mean, p? minutes Submit Question
Researchers sampled fish from a lake and measured the lengths (mm) of all individuals of two species, bream and perch. They were interested in testing whether there was a difference in the mean lengths of the two species in the lake. Based on the output below, what would be the correct conclusion to draw? Mean n Std deviation Std error of mean Bream 531.00 6 309.60 126.39 Perch 154.82 11 78.76 23.75 options: Bream are significantly larger on average than perch in this lake. There is no significant difference in average sizes of the two species of fish from this lake. The variances are different so it is not possible to do a statistical test comparing means. Perch are significantly larger on average than bream in this lake.
The director of research and development is testing a new medicine. She wants to know if there is evidence at the 0.02 level that the medicine relieves pain in more than 346 seconds. For a sample of 58 patients, the mean time in which the medicine relieved pain was 352 seconds. Assume the population standard deviation is 23. Find the P-value of the test statistic. 囲 Tables E Keypad Keyboard Shortcuts 0.0582 %3D IX
z Scores LeBron James, one of the most successful basketball players of all time, has a height of 6 feet 8 inches, or 203 cm. Based on statistics from Data Set 1 “Body Data” in Appendix B, his height converts to the z score of 4.07. How many standard deviations is his height above the mean?
Where are the deer? Random samples of square-kilometer plots were taken in different ecological locations of a national park. The deer counts per square kilometer were recorded and are shown in the following table. Mountain Brush Sagebrush Grassland Pinon Juniper 33 18 10 27 57 4 22 18 2 29 26 13 Shall we reject or accept the claim that there is no difference in the mean number of deer per square kilometer in these different ecological locations? Use a 5% level of significance. (b) Find SSTOT, SSBET, and SSW and check that SSTOT = SSBET + SSW. (Use 3 decimal places.) SSTOT = SSBET = SSW = Find d.f.BET, d.f.W, MSBET, and MSW. (Use 2 decimal places for MSBET, and MSW.) dfBET = dfW = MSBET = MSW = Find the value of the sample F statistic. (Use 3 decimal places.)What are the degrees of freedom? (numerator) (denominator) Make a summary table for your ANOVA test. Source ofVariation Sum ofSquares Degrees ofFreedom MS…

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