5- The wave velocity of ultrasound in soft tissues is 1540m/s and the impedance offered by it is 1.63 X 106 kg/m2 s. What is the density of the soft tissue? a) 0.1058441 kg/m 3 b) 10.58441 kg/m 3 c) 1058.441kg/m 3 d) 105844.1 kg/m 3

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9- Calculate the Doppler frequency, fD, given Incident ultrasound frequency, fi 5.5
MHz Probe angle, 0-45° Blood velocity, v 0.4 m s-1. Speed of sound of muscle, c
= 1590 m s-1.
a- 11.96 Hz
b- 1.96 Hz
c- 119.6 Hz
d- 0.196 Hz
10- The intensity of a 3 MHz ultrasound beam entering tissue is 10 mWcm-2.
Calculate the intensity at a depth of 4 cm. (The attenuation coefficient is 1 dB cm-1
MHz-1.)
a- 6.25 mWcm²
b- 62.5 mWcm²
c- 0.625 mWcm²
d- 625 mWcm²
11- A 5 MHz ultrasound beam incident perpendicularly onto a patient body,
traversing 2 cm of muscle tissue, 3 cm of fat and 4 cm of liver. The tissue properties
are given
CHARACTERISTICS
ACOUSTIC IMPEDANCE,
TISSUE TYPE
Muscle
Z (kg m2 s or rayls)
ATTENUATION
COEFFICIENT, a
(dB cm-' MHz)
1.70 × 10-4
0.6
Fat
1.38 × 10-
1.0
Liver
1.60 x 10-
0.4
5- The wave velocity of ultrasound in soft tissues is 1540m/s and the impedance
offered by it is 1.63 X 106 kg/m2 s. What is the density of the soft tissue?
a) 0.1058441 kg/m 3
b) 10.58441 kg/m 3
c) 1058.441kg/m 3
d) 105844.1 kg/m 3
6. Which of the following relations are true? (y: frequency)
a) y increases, penetration of sound increases, resolution decreases
b) y increases, penetration of sound decreases, resolution decreases
c) y increases, penetration of sound decreases, resolution increases
d) y decreases, penetration of sound increases, resolution increases
7. When an abdominal ultrasound is done, why is it advised to have a full bladder?
a) To have a good acoustic window
b) To increase the water content
c) To lower impedance
d) To allow for better propagation of waves
the reflection index (R) of the signal at the two interfaces
a- 0.0055
b- 0.05
c- 55.0
d- 0.00055
8- The angle of transmission for ultrasound striking the interface between fat and
muscle at an incident angle of 25°. Given the speed of sound for fat and muscle is
1450 ms and 1590 ms, respectively
a- 27.6°
b- 2.76°
c- 276°
d- 90°
Transcribed Image Text:9- Calculate the Doppler frequency, fD, given Incident ultrasound frequency, fi 5.5 MHz Probe angle, 0-45° Blood velocity, v 0.4 m s-1. Speed of sound of muscle, c = 1590 m s-1. a- 11.96 Hz b- 1.96 Hz c- 119.6 Hz d- 0.196 Hz 10- The intensity of a 3 MHz ultrasound beam entering tissue is 10 mWcm-2. Calculate the intensity at a depth of 4 cm. (The attenuation coefficient is 1 dB cm-1 MHz-1.) a- 6.25 mWcm² b- 62.5 mWcm² c- 0.625 mWcm² d- 625 mWcm² 11- A 5 MHz ultrasound beam incident perpendicularly onto a patient body, traversing 2 cm of muscle tissue, 3 cm of fat and 4 cm of liver. The tissue properties are given CHARACTERISTICS ACOUSTIC IMPEDANCE, TISSUE TYPE Muscle Z (kg m2 s or rayls) ATTENUATION COEFFICIENT, a (dB cm-' MHz) 1.70 × 10-4 0.6 Fat 1.38 × 10- 1.0 Liver 1.60 x 10- 0.4 5- The wave velocity of ultrasound in soft tissues is 1540m/s and the impedance offered by it is 1.63 X 106 kg/m2 s. What is the density of the soft tissue? a) 0.1058441 kg/m 3 b) 10.58441 kg/m 3 c) 1058.441kg/m 3 d) 105844.1 kg/m 3 6. Which of the following relations are true? (y: frequency) a) y increases, penetration of sound increases, resolution decreases b) y increases, penetration of sound decreases, resolution decreases c) y increases, penetration of sound decreases, resolution increases d) y decreases, penetration of sound increases, resolution increases 7. When an abdominal ultrasound is done, why is it advised to have a full bladder? a) To have a good acoustic window b) To increase the water content c) To lower impedance d) To allow for better propagation of waves the reflection index (R) of the signal at the two interfaces a- 0.0055 b- 0.05 c- 55.0 d- 0.00055 8- The angle of transmission for ultrasound striking the interface between fat and muscle at an incident angle of 25°. Given the speed of sound for fat and muscle is 1450 ms and 1590 ms, respectively a- 27.6° b- 2.76° c- 276° d- 90°
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