5) Outdoor air enters an air-conditioning system at 10°C and 70% RH at a steady rate of 35 m³/min, and it leaves at 20°C and 60% RH. The outdoor air is first heated to 19.5°C in the heating section and then humidified by the injection of hot steam in the humidifying section. Assuming the entire process takes place at a pressure of 1 atm, determine (a) the rate of heat supply in the heating section and (b) the mass flow rate of steam in the humidifying section.

Elements Of Electromagnetics
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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5) Outdoor air enters an air-conditioning system at 10°C and 70% RH at a steady rate of 35
m³/min, and it leaves at 20°C and 60% RH. The outdoor air is first heated to 19.5°C in the
heating section and then humidified by the injection of hot steam in the humidifying section.
Assuming the entire process takes place at a pressure of 1 atm, determine (a) the rate of heat
supply in the heating section and (b) the mass flow rate of steam in the humidifying section.
Transcribed Image Text:5) Outdoor air enters an air-conditioning system at 10°C and 70% RH at a steady rate of 35 m³/min, and it leaves at 20°C and 60% RH. The outdoor air is first heated to 19.5°C in the heating section and then humidified by the injection of hot steam in the humidifying section. Assuming the entire process takes place at a pressure of 1 atm, determine (a) the rate of heat supply in the heating section and (b) the mass flow rate of steam in the humidifying section.
Expert Solution
Step 1: Calculate the rate of heat supply and the mass flow rate of steam

bold Given bold colon
Outdoor space air space condition comma space straight T subscript 1 equals 10 to the power of straight o straight C space and space straight ϕ subscript 1 equals 70 percent sign
The space volumetric space flow space rate space of space outdoor space air comma space straight V with dot on top subscript 1 equals 35 space straight m cubed divided by min
Exit space air space condition comma space straight T subscript 3 equals 20 to the power of straight o straight C space and space straight ϕ subscript 3 equals 60 percent sign
Temperature space of space air space after space heating comma space straight T subscript 2 equals 19.5 to the power of straight o straight C

bold Find bold colon
open parentheses straight a close parentheses space The space rate space of space heat space supply space in space the space heating space section
open parentheses straight b close parentheses space The space mass space flow space rate space of space steam space in space the space humidifying space section

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