5: Let A = (A) | 1 1 (a): (C)] 1 0 (a) Find a matrix P that diagonalizes A. (b) Find P-¹AP [using your answer from (a)]. (b): Select 2 (A) | 0 0 0 10 0 3 0 0 0 3 (G) 0 Select 0 3 1 0 0 1 0 0 3 0 0 10 0 0 2 0 -10 0 3 1 0 10 (B) 0 1 0 0 0 0 10 10 2 1 0 0 1 (H) | 1 0 2 (B) | 0 0 0 1 10 (H)] 0 0 0 0 3 0 0 3 0 10 0 (C) | 1 0 1 0 1 1 10 0 (C)] 0 10 0 0 0 0 2 1 (D) | 0 0 -2 0 2 0 3 1 0 1 1 1 (E) | 1 0 1 1 10 0 -1 (F) | O 0 10 0 0 0 0 အား အာ (D) 0 3 0 (E) | 0 3 0 0 0 3 0 0 10 0 2 1 0 0 1 (F) | O 0 3 0 0 0 2
5: Let A = (A) | 1 1 (a): (C)] 1 0 (a) Find a matrix P that diagonalizes A. (b) Find P-¹AP [using your answer from (a)]. (b): Select 2 (A) | 0 0 0 10 0 3 0 0 0 3 (G) 0 Select 0 3 1 0 0 1 0 0 3 0 0 10 0 0 2 0 -10 0 3 1 0 10 (B) 0 1 0 0 0 0 10 10 2 1 0 0 1 (H) | 1 0 2 (B) | 0 0 0 1 10 (H)] 0 0 0 0 3 0 0 3 0 10 0 (C) | 1 0 1 0 1 1 10 0 (C)] 0 10 0 0 0 0 2 1 (D) | 0 0 -2 0 2 0 3 1 0 1 1 1 (E) | 1 0 1 1 10 0 -1 (F) | O 0 10 0 0 0 0 အား အာ (D) 0 3 0 (E) | 0 3 0 0 0 3 0 0 10 0 2 1 0 0 1 (F) | O 0 3 0 0 0 2
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
100%
![6: Let
A =
1
(A) 1
1
(a):
(a) Find a matrix P that diagonalizes A.
(b) Find P-¹AP [using your answer from (a)].
1
(G) 1
2 0 10
3 0
0
3
Select ✓
0 3
1
0 1
(G) 0
0
1
0
2 0
(A) 0 3
0
(b): Select
2 0
-10
0
0 3
0 (B) 0
0
0 0
2
0
-1
10
0
0
10
(H) 1
0
1]
1
0 10
1 0 2
1 0
0 1
(H)
1 0
0
2 0
(B) 0 3 0
0
0
3
(C)
(C)
10 0
0
10
0
0
0 2
1
10
0
0
0
2
0
10
0
(D) 0
-2
0
2
(D)
0 3
1
0
1 1
10 0
0 3
0 0
(E) 1
3
0 10
1
0
1
-1
3
(E) 0
0
3
0 0
0
1
0 0
(F) 0
0
0
10
2
0
E
(F) 0 3 0
2
3 00
0 0](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe60e14a8-856f-447c-ac90-795ae43e00b4%2Fba84b087-a540-429d-9d74-ca9e2cff0047%2Fsj5j1s8_processed.png&w=3840&q=75)
Transcribed Image Text:6: Let
A =
1
(A) 1
1
(a):
(a) Find a matrix P that diagonalizes A.
(b) Find P-¹AP [using your answer from (a)].
1
(G) 1
2 0 10
3 0
0
3
Select ✓
0 3
1
0 1
(G) 0
0
1
0
2 0
(A) 0 3
0
(b): Select
2 0
-10
0
0 3
0 (B) 0
0
0 0
2
0
-1
10
0
0
10
(H) 1
0
1]
1
0 10
1 0 2
1 0
0 1
(H)
1 0
0
2 0
(B) 0 3 0
0
0
3
(C)
(C)
10 0
0
10
0
0
0 2
1
10
0
0
0
2
0
10
0
(D) 0
-2
0
2
(D)
0 3
1
0
1 1
10 0
0 3
0 0
(E) 1
3
0 10
1
0
1
-1
3
(E) 0
0
3
0 0
0
1
0 0
(F) 0
0
0
10
2
0
E
(F) 0 3 0
2
3 00
0 0
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