If a polynomial p(x) can be factored as a product of two lower degree polynomials p₁(x) and p2(x) as p(x) = P₁(x)p₂(x) then it can be proved that p(A) = P₁(A)p2(A) for an arbitrary square matrix A. Verify this statement for polynomials p(x) = x² − 9, P₁(x) =x+3, p₂(x) = x − 3. -

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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If a polynomial p(x) can be factored as a product of two lower degree
polynomials p₁ (x) and p₂(x) as
p(x) = P₁(x)p2(x)
then it can be proved that p(A) = P₁(A)p2(A) for an arbitrary square
matrix A. Verify this statement for polynomials
p(x)=x²-9,
P₁(x) = x+3, p2(x) = x - 3.
Transcribed Image Text:If a polynomial p(x) can be factored as a product of two lower degree polynomials p₁ (x) and p₂(x) as p(x) = P₁(x)p2(x) then it can be proved that p(A) = P₁(A)p2(A) for an arbitrary square matrix A. Verify this statement for polynomials p(x)=x²-9, P₁(x) = x+3, p2(x) = x - 3.
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