5) Estimate the mean and standard deviation of the underlying normal distribution from whichthe following data has been generated, using the probability plot method.4.993.735.52-1.834.332.333.672.493.195.401.361.257.424.384.720.273.041.232.88-3.58

Normal Probability Plot: A normal probability plot is a graphical technique for checking whether or…

Answered: 5) Estimate the mean and standard…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Review the plotted data distribution for these 1,000 means. Does this approximate a Normal distribution? Does this confirm the first part of the central limit theorem? Why or why not? Dataframe of 1000 sample means means 0 572.06 1 498.30 2 443.78 3 462.06 4 577.50 .. ... 995 462.46 996 440.42 997 418.64 998 493.66 999 407.42 [1000 rows x 1 columns]
3. Consider a standard normal distribution. a. If z is a standard normal variable, then P(-0.73
Packages of sugar bags for Sweeter Sugar Inc. have an average weight of 16 ounces and a standard deviation of 0.2 ounces. The weights of the sugar packages are normally distributed. What is the probability that 16 randomly selected packages will have a weight less than 16.075 ounces? a. 0.3520 b. 0.6480 c. 0.0668 d. 0.9332
A lawyer commutes daily from his suburban home to his midtown office. The average time for a one-way trip is 24 minutes, with a standard deviation of 3.4 minutes. Assume the distribution of trip times to be normally distributed. Complete parts (a) through (e) below. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. 1 hour? (a) What is the probability that a trip will take at least (Round to four decimal places as needed.)
Find the indicated probability using the standard normal distribution. P(z>1.48) Click here to view page 1 of the standard normal table. LOADING... Click here to view page 2 of the standard normal table. LOADING... Question content area bottom Part 1 P(z>1.48)=enter your response here (Round to four decimal places as needed.) z .09 .08 .07 .06 .05 .04 .03 .02 .01 .00-3.4 .0002 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003 .0003-3.3 .0003 .0004 .0004 .0004 .0004 .0004 .0004 .0005 .0005 .0005-3.2 .0005 .0005 .0005 .0006 .0006 .0006 .0006 .0006 .0007 .0007-3.1 .0007 .0007 .0008 .0008 .0008 .0008 .0009 .0009 .0009 .0010-3.0 .0010 .0010 .0011 .0011 .0011 .0012 .0012 .0013 .0013 .0013-2.9 .0014 .0014 .0015 .0015 .0016 .0016 .0017 .0018 .0018…
1. The weights of bags of baby carrots are normally distributed, with a mean of 34 ounces and a standard deviation of 0.36 ounce. Bags in the upper 4.5% are too heavy and must be repackaged. What is the most a bag of baby carrots can weigh and not need to be repackaged? 2. Find the indicated probability using the standard normal distribution. P(z< 2.23 or z>2.23) 3. Assume the random variable x is normally distributed with mean μ=81 and standard deviation σ =55. Find the indicated probability. P(64<x<74) 4. The monthly utility bills in a city are normally distributed, with a mean of $100 and a standard deviation of $13 Find the probability that a randomly selected utility bill is (a) less than $66 (b) between $86 and $110 and (c) more than $130 please answer all problems
Cans of regular Coke are labeled as containing 12 oz. Statistics students weighed the contents of 8 randomly chosen cans, and found the mean weight to be 12.13 ounces. Assume that cans of Coke are filled so that the actual amounts are normally distributed with a mean of 12.00 oz and a standard deviation of 0.11 oz. Find the probability that a sample of 8 cans will have a mean amount of at least 12.13 oz.
create a normal probability plot.
A recent study focused on the number of times men and women who live alone buy take-out dinner in a month. Assume that the distributions follow the normal probability distribution and the population standard deviations are equal. The information is summarized below. Statistic Men Women Sample mean 24.04 22.15 Sample standard deviation 5.57 4.54 Sample size 32 34 At the 0.01 significance level, is there a difference in the mean number of times men and women order take-out dinners in a month? State the decision rule for 0.01 significance level: H0: μMen= μWomen H1: μMen ≠ μWomen. (Negative values should be indicated by a minus sign. Round your answers to 3 decimal places.) Compute the value of the test statistic. (Round your answer to 3 decimal places.) What is your decision regarding the null hypothesis? What is the p-value? (Round your answer to 3 decimal places.)
Given a normal probability distribution with a mean of 9% and a standard deviation of 4%, what is the probability of observing a value between 2% and 14%? Use the following Z-score data is from the HP calculator: Z-Score -2.00 -1.75 -1.50 -1.25 -1.00 0.00 1.00 1.25 1.50 1.75 2.00 Probability 0.0228 0.0401 0.0668 0.1056 0.1587 0.5000 0.8413 0.8944 0.9332 0.9599 0.9772 Answer in decimal format, to 3 decimal places, truncated. For example, if your answer is 33.46%, enter 0.334.
Suppose a sample of O-rings was obtained and the wall thickness (in inches) of each was recorded. Use a normal probability plot to assess whether the sample data could have come from a population that is normally distributed. 0.163 0.182 0.194 0.211 0.224 0.225 0.233 0.243 0.251 0.259 0.271 0.273 0.295 0.307 0.317 0.340 Click here to view the table of critical values for normal probability plots. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. Using the correlation coefficient of the normal probability plot, is it reasonable to conclude that the population is normally distributed? Select the correct choice below and fill in the answer boxes within your choice. (Round to three decimal places as needed.) A. No. The correlation between the expected z-scores and the observed data, normal population. does not exceed the critical value, Therefore, it is not reasonable to conclude that the data come from…
What is the probability that a sample will have a z-score of more than 2.90? Z 0.0 2.50.99380.99400.99410.9943 2.60.99530.99550.99560.9957 2.70.99650.99660.99670.9968 2.80.99740.99750.99760.9977 2.90.99810.99820.99820.9983 0.01 0.02 0.03 99.81% O 0.19% 19.00% 0.9981% ere to search F7 F8 F9 F10 E3 F4 F5 F6 2$ % 6 7 8 9 2 3 W R

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5) Estimate the mean and standard deviation of the underlying normal distribution from which the following data has been generated, using the probability plot method. 3.73 4.72 0.27 -1.83 4.99 2.49 4.33 2.33 5.40 1.36 4.38 2.88 3.67 1.25 3.04 1.23 3.19 5.52 -3.58 7.42