An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 120 lb and 161 lb. The new population of pillots has normally distributed weights with a mean of 128 lb and a standard deviation of 32.1 lb. Click here to view page 1 of the standard normal distribution. Click here to view page 2 of the standard normal distribution. a. If a pilot is randomly selected, find the probability that his weight is between 120 lb and 161 It The probability is approximately (Round to four decimal places as needed.) Standard normal distribution table (page 2) Standard Normal (2) Distribution: Cumulative Area from the LEFT 2 00 .00 cm 01 02 5040 5080 03 5120 .04 5160 .05 5199 06 5239 07 5279 08 09 5319 5359

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 120 lb and 161 lb. The new population of pilots has normally distributed weights
with a mean of 128 lb and a standard deviation of 32.1 lb.
Click here to view page 1 of the standard normal distribution.
Click here to view page 2 of the standard normal distribution.
a. If a pilot is randomly selected, find the probability that his weight is between 120 lb and 161 lb
The probability is approximately. (Round to four decimal places as needed.)
View an example
2
3
W
S
X
H
ommand
#
3
Get more help.
80
F3
E
D
C
$
4
F4
R
F
%
5
V
I
F5
T
G
6
B
MacBook Air
Y
H
&
7
44
N
U
*
8
Standard normal distribution table (page 2)
Standard Normal (z) Distribution: Cumulative Area from the LEFT
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Transcribed Image Text:x An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 120 lb and 161 lb. The new population of pilots has normally distributed weights with a mean of 128 lb and a standard deviation of 32.1 lb. Click here to view page 1 of the standard normal distribution. Click here to view page 2 of the standard normal distribution. a. If a pilot is randomly selected, find the probability that his weight is between 120 lb and 161 lb The probability is approximately. (Round to four decimal places as needed.) View an example 2 3 W S X H ommand # 3 Get more help. 80 F3 E D C $ 4 F4 R F % 5 V I F5 T G 6 B MacBook Air Y H & 7 44 N U * 8 Standard normal distribution table (page 2) Standard Normal (z) Distribution: Cumulative Area from the LEFT .01 .05 z 0.0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1.0 1.1 1.2 1.3 1.4 1.5 1.6 1.7 1.8 1.9 2.0 DII F8 1 M .00 5000 5398 5793 6179 6554 6915 7257 .7580 .7881 8159 8413 8643 8849 9032 9192 9332 9452 K ( 9 .03 .04 5120 5080 5160 5040 5438 5478 5517 5557 5832 5871 .5910 5948 .6255 6293 6217 .6331 6700 .6591 6628 6950 .6985 .7054 7291 7389 7704 7995 8264 8485 8508 6664 7019 7357 7324 7611 7673 7910 .7967 8238 8708 8907 9082 9236 9357 9370 9484 9582 9664 9732 9738 8186 8438 8665 8869 9049 9207 9345 9463 9474 9554 9564 9649 .9641 9713 9719 9778 9772 nase DD F9 O I .02 дв .7642 .7939 8212 8461 8686 8888 9066 9222 9573 9656 9726 9783 ) O L Print 9788 9793 MARE nara command F10 P . 8729 8749 8925 8944 9099 9115 9265 : ; 5239 5199 5636 5596 5987 6026 6406 6368 6772 6736 7123 .7088 .7157 7486 7422 7454 7764 7734 7794 8023 8051 8078 8340 8289 8315 8531 8554 8577 8770 Done F11 I option { [ 06 8962 9131 9251 9279 9418 9429 9441 9535 9525 9545 9625 9633 9382 9394 9406 9505 9615 9496 9608 9599 9591 9678 9686 9699 9744 9750 9756 9761 9767 9608 9817 9803 9798 9616 9693 9671 9706 9812 NOEL nowe AACA + ? .07 5279 5675 6064 .6443 6808 1 8790 8960 9147 9292 11 T I .08 .09 5359 5319 5714 .5753 6103 6141 6517 6480 6844 .7190 7517 7823 8106 8366 8599 8810 8997 9162 9306 F12 Show All ] 6879 7224 7549 7852 8133 8389 8621 8830 9015 9177 9319 X delete 0 retu
←
An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 120 lb and 161 lb. The new population of pilots has normally distributed weights
with a mean of 128 lb and a standard deviation of 32.1 lb.
Click here to view page 1 of the standard normal distribution.
Click here to view page 2 of the standard normal distribution.
Xx
a. If a pilot is randomly selected, find the probability that his weight is between 120 lb and 161
The probability is approximately. (Round to four decimal places as needed.)
View an example
2
F2
W
S
X
H
ommand
3
Get more help.
80
F3
E
D
C
$
4
Q
FA
R
F
%
5
V
FS
T
G
6
B
MacBook Air
Y
H
&
7
N
F7
U
*
8
Standard normal distribution table (page 1)
D
Standard Normal (z) Distribution: Cumulative Area from the LEFT
.01
.06
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Transcribed Image Text:← An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 120 lb and 161 lb. The new population of pilots has normally distributed weights with a mean of 128 lb and a standard deviation of 32.1 lb. Click here to view page 1 of the standard normal distribution. Click here to view page 2 of the standard normal distribution. Xx a. If a pilot is randomly selected, find the probability that his weight is between 120 lb and 161 The probability is approximately. (Round to four decimal places as needed.) View an example 2 F2 W S X H ommand 3 Get more help. 80 F3 E D C $ 4 Q FA R F % 5 V FS T G 6 B MacBook Air Y H & 7 N F7 U * 8 Standard normal distribution table (page 1) D Standard Normal (z) Distribution: Cumulative Area from the LEFT .01 .06 Z -3.50 and lower 0001 -3.4 <-3.3 -3.2 -3.1 -3.0 -2.9 -2.8 -2.7 -2.6 -2.5 -2.4 -2.3 -2.2 -2.1 -2.0 -1.9 -1.8 Dil 1 ,00 M 0287 0359 9 K DD O < 0004 .0003 .0003 0003 0003 .0003 0003 .0005 .0005 0006 0004 0004 0007 .0007 0006 0006 0006 0006 .0010 .0009 .0009 0009 0008 0008 ,0013 0013 0012 0012 0011 .0018 0018 0017 0016 0016 0023 0022 0031 0030 .0029 0040 .0003 0003 .0003 .0002 .0004 0004 0004 .0003 .0006 0005 0005 0005 .0008 .0008 0007 0007 0010 .0011 0011 0010 0015 0015 0021 0013 0019 .0014 0014 .0026 .0025 0024 0023 0021 0020 0019 0035 .0034 0033 0032 0028 0027 0026 0044 0043 0041 0037 0036 0047 .0045 0062 .0060 0038 0051 0049 0067 0054 .0039 .0052 .0069 0048 0059 0080 0078 0082 0107 0104 0102 0075 .0071 0068 .0066 .0064 0094 .0091 0087 0084 0089 0116 0132 0122 0113 0110 .0136 0139 0179 .0174 0119 0158 0154 0150 0146 0143 0228 0170 0217 0274 .0281 0222 0197 0192 0183 0188 02:39 0233 0256 .0250 0244 0307 0314 0344 0351 0322 0294 0301 I .02 дв ) O L .03 .0099 0129 0166 0212 0268 0336 command F10 P .04 V 0055 .0073 0096 0125 .05 0162 0202 0207 0262 0329 - .... di F11 { I option [ + = ? 1 .07 11 Show All AM .08 F12 } 09 1 X delete P ret
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