5 cm 5 cm R = - P = JAV 20 cm 12 V P = l*R = AV² %3D A rectangular resistor is connected with 12 V battery. The resistivity p is 10 Q· m. What is the power of this resistor when the circuit is running?

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A: Given that, R1=20Ω, P=5 W and V=24 V.

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Q: power is dissipated

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Q: In the figure, the total resistance is 11.4 k, and the battery's emf is 29.8 V. If the time constant…

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