The figure shows an ideal battery of emf € = 13 V, a resistorof resistance R = 6.3 M2, and an uncharged capacitor ofcapacitance C = 6.3 μF. After switch S is closed, what isthe current through the resistor when the charge on thecapacitor is 9.5 μC?4R

The objective of the question is to find the current through the resistor when the charge on the capacitor is 9.5 μC in a circuit consisting of a battery, a resistor, and a capacitor.First, we need to understand that the voltage across the capacitor and resistor is the same in this circuit configuration. The voltage across the capacitor (Vc) can be calculated using the formula Vc = Q/C, where Q is the charge on the capacitor and C is the capacitance of the capacitor.Substituting the given values, we get Vc = 9.5 μC / 6.3 μF = 1.5 V.Next, we calculate the voltage across the resistor (Vr), which is the difference between the emf of the battery (E) and the voltage across the capacitor (Vc). So, Vr = E - Vc.Substituting the given values, we get Vr = 13 V - 1.5 V = 11.5 V.Finally, we can calculate the current (I) through the resistor using Ohm's law, which states that I = V/R, where V is the voltage across the resistor and R is the resistance of the resistor.Substituting the given values, we get I = 11.5 V / 6.3 MΩ = 1.82 μA.The current through the resistor when the charge on the capacitor is 9.5 μC is calculated to be 1.82 μA. This is done by first calculating the voltage across the capacitor and the resistor, and then using Ohm's law to find the current.

Answered: The figure shows an ideal battery of…

The figure shows an ideal battery of emf € = 13 V, a resistor of resistance R = 6.3 M2, and an uncharged capacitor of capacitance C = 6.3 μF. After switch S is closed, what is the current through the resistor when the charge on the capacitor is 9.5 μC? 4 R