5 [a] A particle falls to Earth starting at a great height (many times the Earth's radius). Neglecting the air resistance show that the particle takes about of the total time of the fall, in traveling the first half of the distance. (b) A particle at rest is attracted towards a center of force according to the relation F = -mk²/r³. Show that the time required to reach the force-center from a distance d is given by d²/k.
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- A particle is launched from the origin on the ground with an initialvelocity? = (2.40 m/s) ? + (2.00 m/s) ?. The particle falls freely under earth’sgravitational field.A body of mass m is attracted toward a 11.1 kg mass, 31.5 cm away, with a force of magnitude 6.60 10-8 N. Find m. can you also add the units!The proton is traveling at a constant speed of 5.5 × 105 m/s, and the radius of the kissing circle is 0.02 m. The mass of a proton is 1.7 × 10-27 kg. When the proton is at location A, what are the magnitude and direction (d|p→|/dt)(p^) of the parallel component of dp→/dt?
- Consider two iron spheres, each of diameter 145 mm, which are just touching. At what distance r from the center of the earth will the force of mutual attraction between the contacting spheres be equal to the force exerted by the earth on one of the spheres? Answer: r- i (107) kmCopied! Problems us rce *24 Compute the orbital radius of an earth satellite that has an equatorial orbit and always remains above a fixed point P on the earth's surface. Communication satel- lites have such "geosynchronous" orbits (Fig. 6-19). These satellites are used to relay radio and television signals around the world. s if un- hate Communication satellite wwwwwwww as a dius mmm Fig. 6-19 25 The earth orbits the sun in an approximately circular orbit of radius 1.496 X 10" m (about 93 million 152) A positron (positively charged electron) with a kinetic energy of 3.6 x 10-18 J is projected into a uniform magnetic field B = 420 µT with its velocity vector making an angle of 60° with B. Because the particle has components of velocity both parallel and perpendicular to the magnetic field, it moves in a spiral. Find the period, pitch p and radius r of the helical path. (Pitch is the distance it moves forward during a period.)
- I Review I Constants A uniform, solid, 1900.0 kg sphere has a radius of 5.00 m. Part A For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Journey to the center of the earth. Find the gravitational force this sphere exerts on a 1.70 kg point mass placed at the following distances from the center of the sphere 5.03 m. Express your answer in newtons. ΑΣφ ? F = N Submit Request Answer Part B Find the gravitational force this sphere exerts on a 1.70 kg point mass placed at the following distances from the center of the sphere 2.30 m. Express your answer in newtons. ? F = NTwo masses m1and m2 with a separation distance of d, attract each with a force F. What is the relationship between the F and the separation distance d? ii. By what factor will the force of attraction change if the separationdistance changes to 0.25d?A star of radius 67000 km and mass equal to that of the Sun has two small planets moving around it on circular orbits. The radius of the first planet's orbit is 100 times the radius of the star. It is known that the kinetic energy of the orbital motion of the second planet is equal in magnitude to the potential energy of the first planet in the field of the star. What is the radius of the second planet's orbit if it is 8 times heavier than the first planet?
- A uranium ion and an iron ion are separated by a distance of ?=57.10 nm, as shown in the figure. The uranium atom is singly ionized; the iron atom is doubly ionized. Calculate the distance ? from the uranium atom at which an electron will be in equilibrium. Ignore the gravitational attraction between the particles. ?= What is the magnitude ?U of the force on the electron from the uranium ion?What is the smallest value of B that can be set up at the equator to permit a proton of speed 10 m/s to circulate around the earth? (R = 6.4× 106 m, m = 1.67 × 10² kg).A satellite of mass 180 kg is placed into Earth orbit at a height of 500 km above the surface. (a) Assuming a circular orbit, how long does the satellite take to complete one orbit? 1656 X It may be easiest to answer part (b) (find the speed of the satellite) first. h (b) What is the satellite's speed? 11.174 X If you know the net force acting on an object that moves in a circle, how can you calculate its speed? m/s (c) Starting from the satellite on the Earth's surface at the equator, what is the minimum energy input necessary to place this satellite in orbit? Ignore air resistance but include the effect of the planet's daily rotation. J