Hello,I don't understand how to solve 5-9 in the photo below. Because I can't find the correct elaboration on the solutions, I hope that you can show me how to get to this answer. I have added my own calculations in a photo for your insight.These are the correct answers:T1 max = 2,37 kNmtmaxCD = 35,6 MPatmaxDE = 23,3 MPaThanks for your help!Julia Q=So mmIattow= 60 MPa.=Tmax%3DMp=30Mc=600 NomT=-MgMA= goos00 +600 +goo = MR= ItNM=T.NM1800-Ic4= T (0,025)"= 6, 14-10my%3D2of60-0°O T=Imax=Tc/]0,025 = 24 :1012 Pa6,14-107 Prob. 5-85-9. The solid aluminum shaft has a diameter of 50 mmand an allowable shear stress of Tallow = 60 MPa. Determinethe largest torque T that can be applied to the shaft if it isalso subjected to the other torsional loadings. It is requiredthat T act in the direction shown. Also, determine themaximum shear stress within regions CD and DE.ndheheThe solid aluminum shaft has a diameter of 50 mm.Determine the absolute maximum shear stress in the shaft andsketch the shear-stress distribution along a radial line of theshaft where the shear stress is maximum. Set T=2000 N m.onimmsiob mm 001 ai finde oumizom oil sd bluow terW.bottimanei sd nodoro erla srs dauond bonod ensw slord zstomsib-mm-sseo rbss ni onil Isibern gnols noludiaib a2ate-18ada sd5-10.ED300 N-mВ600 N-mT1900 N-mProbs. 5-9/10

Given: The diameter of the shaft, d = 50 mm The allowable shear stress = 60 MPa

Answered: 5-9. The solid aluminum shaft has a…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Hello,

I don't understand how to solve 5-9 in the photo below. Because I can't find the correct elaboration on the solutions, I hope that you can show me how to get to this answer. I have added my own calculations in a photo for your insight.

These are the correct answers:

T1 max = 2,37 kNm

tmaxCD = 35,6 MPa

tmaxDE = 23,3 MPa

Thanks for your help!

Julia

Q=So mm
Iattow= 60 MPa.
=Tmax
%3D
Mp=30
Mc=600 Nom
T=-Mg
MA= goo
s00 +600 +goo = MR= It
NM=T.
NM
1800
-Ic4= T (0,025)"= 6, 14-10
my
%3D
2
of
60-0°
O T=
Imax=Tc/]
0,025 = 24 :1012 Pa
6,14-107

Prob. 5-8
5-9. The solid aluminum shaft has a diameter of 50 mm
and an allowable shear stress of Tallow = 60 MPa. Determine
the largest torque T that can be applied to the shaft if it is
also subjected to the other torsional loadings. It is required
that T act in the direction shown. Also, determine the
maximum shear stress within regions CD and DE.
nd
he
he
The solid aluminum shaft has a diameter of 50 mm.
Determine the absolute maximum shear stress in the shaft and
sketch the shear-stress distribution along a radial line of the
shaft where the shear stress is maximum. Set T=2000 N m.
onimmsiob mm 001 ai finde o
umizom oil sd bluow terW.bottimanei sd no
doro erla srs dauond bonod ensw slord zstomsib-mm-s
seo rbss ni onil Isibern gnols noludiaib a2ate-18ada sd
5-10.
E
D
300 N-m
В
600 N-m
T1
900 N-m
Probs. 5-9/10

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