5 9 What is the pH of a 2.15 M solution of NH4Cl (Kp of NH3= 1.8 x 10-5)? Your Answer: Answer

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**Problem Statement:**

What is the pH of a 2.15 M solution of NH₄Cl (K_b of NH₃ = 1.8 x 10⁻⁵)?

**Solution Explanation:**

To find the pH of an NH₄Cl solution, follow these steps:

1. **Understand the Dissociation:**
   - NH₄Cl dissociates in water into NH₄⁺ and Cl⁻ ions.
   - NH₄⁺ is the conjugate acid of NH₃.

2. **Relation of K_b and K_a:**
   - Use the relation: \( K_w = K_a \times K_b \)
   - \( K_w \) (ion-product constant of water) is \( 1.0 \times 10^{-14} \).

3. **Calculate K_a:**
   - Rearrange to find K_a: \( K_a = \frac{K_w}{K_b} \)
   - Substitute values: \( K_a = \frac{1.0 \times 10^{-14}}{1.8 \times 10^{-5}} \)

4. **Set up the Equilibrium Expression:**
   - For the reaction: NH₄⁺ ⇌ NH₃ + H⁺
   - Use: \( K_a = \frac{[NH₃][H⁺]}{[NH₄⁺]} \)

5. **Calculate [H⁺]:**
   - Assume initial concentration of NH₄⁺ is 2.15 M.
   - Apply ICE table approach assuming ‘x’ is the concentration of H⁺ formed.

6. **Solve for pH:**
   - Calculate x (the concentration of H⁺).
   - Use the formula: \( \text{pH} = -\log[H⁺] \)

This approach allows you to calculate the pH of the NH₄Cl solution.
Transcribed Image Text:**Problem Statement:** What is the pH of a 2.15 M solution of NH₄Cl (K_b of NH₃ = 1.8 x 10⁻⁵)? **Solution Explanation:** To find the pH of an NH₄Cl solution, follow these steps: 1. **Understand the Dissociation:** - NH₄Cl dissociates in water into NH₄⁺ and Cl⁻ ions. - NH₄⁺ is the conjugate acid of NH₃. 2. **Relation of K_b and K_a:** - Use the relation: \( K_w = K_a \times K_b \) - \( K_w \) (ion-product constant of water) is \( 1.0 \times 10^{-14} \). 3. **Calculate K_a:** - Rearrange to find K_a: \( K_a = \frac{K_w}{K_b} \) - Substitute values: \( K_a = \frac{1.0 \times 10^{-14}}{1.8 \times 10^{-5}} \) 4. **Set up the Equilibrium Expression:** - For the reaction: NH₄⁺ ⇌ NH₃ + H⁺ - Use: \( K_a = \frac{[NH₃][H⁺]}{[NH₄⁺]} \) 5. **Calculate [H⁺]:** - Assume initial concentration of NH₄⁺ is 2.15 M. - Apply ICE table approach assuming ‘x’ is the concentration of H⁺ formed. 6. **Solve for pH:** - Calculate x (the concentration of H⁺). - Use the formula: \( \text{pH} = -\log[H⁺] \) This approach allows you to calculate the pH of the NH₄Cl solution.
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