to 1 MPa and 30°C in a condenser by air. The air enters at5-81 Refrigerant-134a at 1 MPa and 90°C is to be cooledand leaves at 95 kPa and 60°C. Determine the mass flow rate100 kPa and 27°C with a volume flow rate of 600 m’/minof the refrigerant. Answer: 100 kg/minAirV3 = 600 m³/minP3 = 100 kPa|T3 = 27°C%3D%3DR-134aboleP1 = 1 MPaT = 90°CP4 = 95 kPaT4 = 60°CP2 = 1 MPaT2 = 30°C%3DFIGURE P5-81window air

Answered: Image /qna-images/answer/110a785d-7553-415f-a127-de12e857d07c.jpg

5-81 Refrigerant-134a at 1 MPa and 90°C is to be cooled and leaves at 95 kPa and 60°C. Determine the mass flow rate to 1 MPa and 30°C in a condenser by air. The air enters at 100 kPa and 27°C with a volume flow rate of 600 m³/min of the refrigerant. Answer: 100 kg/min Air V3 = 600 m³/min P3 = 100 kPa T3 = 27°C %3D %3D %3D R-134a t bonhe P = 1 MPa T = 90°C %3D %3D P4 = 95 kPa T4 = 60°C P2 = 1 MPa T2 = 30°C %3D %3D

5-81 Refrigerant-134a at 1 MPa and 90°C is to be cooled and leaves at 95 kPa and 60°C. Determine the mass flow rate to 1 MPa and 30°C in a condenser by air. The air enters at 100 kPa and 27°C with a volume flow rate of 600 m³/min of the refrigerant. Answer: 100 kg/min Air V3 = 600 m³/min P3 = 100 kPa T3 = 27°C %3D %3D %3D R-134a t bonhe P = 1 MPa T = 90°C %3D %3D P4 = 95 kPa T4 = 60°C P2 = 1 MPa T2 = 30°C %3D %3D

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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Question

to 1 MPa and 30°C in a condenser by air. The air enters at
5-81 Refrigerant-134a at 1 MPa and 90°C is to be cooled
and leaves at 95 kPa and 60°C. Determine the mass flow rate
100 kPa and 27°C with a volume flow rate of 600 m’/min
of the refrigerant. Answer: 100 kg/min
Air
V3 = 600 m³/min
P3 = 100 kPa|
T3 = 27°C
%3D
%3D
R-134a
bole
P1 = 1 MPa
T = 90°C
P4 = 95 kPa
T4 = 60°C
P2 = 1 MPa
T2 = 30°C
%3D
FIGURE P5-81
window air

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