5-7. For each function f and interval [a, b], a graph of ƒ is given along with the secant line that passes though the graph of f at a and x = b. a. Use the graph to make a conjecture about the value(s) of c satisfy- f(b) - f(a) - f'(c). b - a ing the equation b. Verify your answer to part (a) by solving the equation f(b) – f(a) b - a = f'(c) for c. x2 f(x) = ÷ + 1; [-2, 4] yA 6- 5- 4- y = +1 -3 -2 -1 2 5 X 3. 2.
5-7. For each function f and interval [a, b], a graph of ƒ is given along with the secant line that passes though the graph of f at a and x = b. a. Use the graph to make a conjecture about the value(s) of c satisfy- f(b) - f(a) - f'(c). b - a ing the equation b. Verify your answer to part (a) by solving the equation f(b) – f(a) b - a = f'(c) for c. x2 f(x) = ÷ + 1; [-2, 4] yA 6- 5- 4- y = +1 -3 -2 -1 2 5 X 3. 2.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
![5-7. For each function f and interval [a, b], a graph of ƒ is given
along with the secant line that passes though the graph of f at a
and x = b.
a. Use the graph to make a conjecture about the value(s) of c satisfy-
f(b) - f(a) - f'(c).
b - a
ing the equation
b. Verify your answer to part (a) by solving the equation
f(b) – f(a)
b - a
= f'(c) for c.
x2
f(x) = ÷ + 1; [-2, 4]
yA
6-
5-
4-
y =
+1
-3 -2 -1
2
5 X
3.
2.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb9695966-be60-491d-b253-c186970e20a2%2Fd9a1610e-1a97-4da3-a26d-e59814192f23%2F90372r.png&w=3840&q=75)
Transcribed Image Text:5-7. For each function f and interval [a, b], a graph of ƒ is given
along with the secant line that passes though the graph of f at a
and x = b.
a. Use the graph to make a conjecture about the value(s) of c satisfy-
f(b) - f(a) - f'(c).
b - a
ing the equation
b. Verify your answer to part (a) by solving the equation
f(b) – f(a)
b - a
= f'(c) for c.
x2
f(x) = ÷ + 1; [-2, 4]
yA
6-
5-
4-
y =
+1
-3 -2 -1
2
5 X
3.
2.
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