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5 6 3 B 9 O 1 2 5 6 3 4 B 12.7 mm L= 0.4 m 3 B 9 1 2 3 4 5 Load (W) (N) 0 5 10 15 20 25 5 Formula: W (N) L^3 Problem # 4 Hollow Aluminium - Simply Supported Deflection (▲) (mm) 48 A1/L³ E I 0 0.064 0.128 0.192 0.256 0.32 Experiment 2 b= 9.5 mm L³ = 0.064m Formula: WL³ 48 x EXI Given: 0,5,10,15,20,25 0.4^3 69 x 10⁹ Pa 1.51*10^-10 48 AI Material: Hollow Aluminium h= 9.5 mm H = 12.7 mm 1 = 1.51 x 10⁹ Formula: Formula: 48 x (A) 0.064 x (1) 1.51 x 1048 x (A) 0.064 × (1) 1.51 × 10⁹ 0.064

5 6 3 B 9 O 1 2 5 6 3 4 B 12.7 mm L= 0.4 m 3 B 9 1 2 3 4 5 Load (W) (N) 0 5 10 15 20 25 5 Formula: W (N) L^3 Problem # 4 Hollow Aluminium - Simply Supported Deflection (▲) (mm) 48 A1/L³ E I 0 0.064 0.128 0.192 0.256 0.32 Experiment 2 b= 9.5 mm L³ = 0.064m Formula: WL³ 48 x EXI Given: 0,5,10,15,20,25 0.4^3 69 x 10⁹ Pa 1.51*10^-10 48 AI Material: Hollow Aluminium h= 9.5 mm H = 12.7 mm 1 = 1.51 x 10⁹ Formula: Formula: 48 x (A) 0.064 x (1) 1.51 x 1048 x (A) 0.064 × (1) 1.51 × 10⁹ 0.064

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Need help with the math in the remaining colums i am doing something wrong

5 67 -6 8 -9 0 1 2 3 4 B= 12.7 mm 5 L= 0.4 m 6 7 6 8 9 -0 -1 2 -3 4 st Load (W) (N) 0 5 10 15 20 25 5 6 сл Formula: W (N) L^3 B Problem #4 Hollow Aluminium - Simply Supported Deflection (▲) (mm) 48 A1/L³ E I 0 0.064 0.128 0.192 0.256 0.32 Experiment 2 b= 9.5 mm L³ = 0.064m Formula: 3 WL³ 48 x Exl Given: 0,5,10,15,20,25 0.4^3 69 x 10⁹ Pa 1.51*10^-10 48 AI Material: Hollow Aluminium h= 9.5 mm H = 12.7 mm I = 1.51 x 10⁹ Formula: 48 x (A) 0.064 x (1) 1.51 x 10⁹ 48 x Formula: ) 0.064 x (1) 1.51 x 10⁹ 0.064
Transcribed Image Text:5 67 -6 8 -9 0 1 2 3 4 B= 12.7 mm 5 L= 0.4 m 6 7 6 8 9 -0 -1 2 -3 4 st Load (W) (N) 0 5 10 15 20 25 5 6 сл Formula: W (N) L^3 B Problem #4 Hollow Aluminium - Simply Supported Deflection (▲) (mm) 48 A1/L³ E I 0 0.064 0.128 0.192 0.256 0.32 Experiment 2 b= 9.5 mm L³ = 0.064m Formula: 3 WL³ 48 x Exl Given: 0,5,10,15,20,25 0.4^3 69 x 10⁹ Pa 1.51*10^-10 48 AI Material: Hollow Aluminium h= 9.5 mm H = 12.7 mm I = 1.51 x 10⁹ Formula: 48 x (A) 0.064 x (1) 1.51 x 10⁹ 48 x Formula: ) 0.064 x (1) 1.51 x 10⁹ 0.064
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