5) (11.3) A store once claimed that male employees and female employees earn the same on average. A worker's spouse at that same local store wondered if men at her store made more on average and decided to run a study. Of 65 female employees who were randomly selected, it was found that their mean monthly income was $640 with a standard deviation of $121.50. Of seventy-five male employees who were also randomly selected, their mean monthly income was found to be $682 with a standard deviation of $168.70. Test the spouse's claim that male employees earn more than female employees on average. Use a = 0.01. Label your Ho and H₁, determine the p-value, state whether you reject or don't reject Ho then state a formal conclusion.
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- Participants were enrolled in a health-coaching program for eight weeks to try to improve physical health and overall wellness. At the end of the trial period, the participants take a personal health improvement survey. The mean health improvement survey score for all participants in the program was 74.4 with a standard deviation of 10.3. We have reason to think that one of the health coaches (Coach A) who participated in an additional training program will have subjects who have higher health improvement survey scores than the overall program average. We know that Coach A trains 30 subjects with the average health improvement survey score of 80.1. a) We want to test the hypothesis that subjects who work with Coach A have higher health improvement survey scores compared with the rest of the program participants. Use alpha of 0.05 b) Suppose a continuous random variable can only take on values between −1 and +1 on a standard normal curve, what is the area under the curve? Use…One year Perry had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at his school, with an ERA of 2.57. Also, Rita had the lowest ERA of any female pitcher at the school with an ERA of 3.26. For the males, the mean ERA was 4.304 and the standard deviation was 0.894. For the females, the mean ERA was 4.158 and the standard deviation was 0.519. Find their respective z-scores. Which player had the better year relative to their peers, Perry or Rita? (Note: In general, the lower the ERA, the better the pitcher.) Perry had an ERA with a z-score of Rita had an ERA with a z-score of (Round to two decimal places as needed.) Textbook Get more help - $ 1 G Search or type URL % 31 6 & 7 * 8 + ( 9 0 Clear all + Check answer deleteOne year Terry had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at his school, with an ERA of 3.02. Also, Karen had the lowest ERA of any female pitcher at the school with an ERA of 3.24. For the males, the mean ERA was 4.364 and the standard deviation was 0.639. For the females, the mean ERA was 3.801 and the standard deviation was 0.959 Find their respective z-scores. Which player had the better year relative to their peers, Terry or Karen? (Note: In general, the lower the ERA, the better the pitcher.) Terry had an ERA with a z-score of Karen had an ERA with a z-score of (Round to two decimal places as needed) Which player had a better year in comparison with their peers? OA. Terry had a better year because of a higher z-score. OB. Karen had a better year because of a lower z-score. OC. Terry had a better year because of a lower z-score. O D. Karen had a better year because of a higher z-score. GIL
- Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 37 randomly selected people who train in groups, and finds that they run a mean of 47.7 miles per week. Assume that the population standard deviation for group runners is known to be 3.3 miles per week. She also interviews a random sample of 49 people who train on their own and finds that they run a mean of 49.4 miles per week. Assume that the population standard deviation for people who run by themselves is 4.4 miles per week. Test the claim at the 0.10 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.Fran is training for her first marathon, and she wants to know if there is a significant difference between the mean number of miles run each week by group runners and individual runners who are training for marathons. She interviews 42 randomly selected people who train in groups and finds that they run a mean of 47.1 miles per week. Assume that the population standard deviation for group runners is known to be 4.4 miles per week. She also interviews a random sample of 47 people who train on their own and finds that they run a mean of 48.5 miles per week. Assume that the population standard deviation for people who run by themselves is 1.8 miles per week. Test the claim at the 0.01 level of significance. Let group runners training for marathons be Population 1 and let individual runners training for marathons be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 1010 days following no advertisements, the mean was 18.618.6 purchasing customers with a standard deviation of 1.51.5 customers. On 77 days following advertising, the mean was 20.320.3 purchasing customers with a standard deviation of 0.90.9 customers. Test the claim, at the 0.020.02 level, that the mean number of customers who make a purchase in the store is lower for days following no advertising compared to days following advertising. Assume that both populations are approximately normal and that the population variances are equal. Let days following no advertisements be Population 1 and let days following advertising be Population 2.…
- A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 10 days following no advertisements, the mean was 18.3 purchasing customers with a standard deviation of 1.8 customers. On 7 days following advertising, the mean was 19.4 purchasing customers with a standard deviation of 1.6 customers. Test the claim, at the 0.02 level, that the mean number of customers who make a purchase in the store is lower for days following no advertising compared to days following advertising. Assume that both populations are approximately normal and that the population variances are equal. Let days following no advertisements be Population 1 and let days following advertising be Population 2. Step 3 of 3: Draw a…A report about how American college students manage their finances includes data from a survey of college students. Each person in a representative sample of 793 college students was asked if they had one or more credit cards and if so, whether they paid their balance in full each month. There were 500 who paid in full each month. For this sample of 500 students, the sample mean credit card balance was reported to be $825. The sample standard deviation of the credit card balances for these 500 students was not reported, but for purposes of this exercise, suppose that it was $205. Is there convincing evidence that college students who pay their credit card balance in full each month have a mean balance that is lower than $907, the value reported for all college students with credit cards? Carry out a hypothesis test using a significance level of 0.01. State the appropriate null and alternative hypotheses. H0: ? = 907 Ha: ? < 907 H0: ? = 907 Ha: ? > 907 H0: ? < 907…A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 7 days following no advertisements, the mean was 22.1 purchasing customers with a standard deviation of 1.2 customers. On 10 days following advertising, the mean was 24.1 purchasing customers with a standard deviation of 1.6 customers. Test the claim, at the 0.05 level, that the mean number of customers who make a purchase in the store is lower for days following no advertising compared to days following advertising. Assume that both populations are approximately normal and that the population variances are equal. Let days following no advertisements be Population 1 and let days following advertising be Population 2. Step 1 of 3: State the…
- A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 13 days following no advertisements, the mean was 23.9 purchasing customers with a standard deviation of 1.9 customers. On 6 days following advertising, the mean was 24.7 purchasing customers with a standard deviation of 1.6 customers. Test the claim, at the 0.01 level, that the mean number of customers who make a purchase in the store is lower for days following no advertising compared to days following advertising. Assume that both populations are approximately normal and that the population variances are equal. Let days following no advertisements be Population 1 and let days following advertising be Population 2. Step 3 of 3: Draw a…One year Hank had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at his school, with an ERA of 3.09. Also, Karen had the lowest ERA of any female pitcher at the school with an ERA of 2.98. For the males, the mean ERA was 4.635 and the standard deviation was 0.576. For the females, the mean ERA was 4.469 and the standard deviation was 0.944. Find their respective z-scores. Which player had the better year relative to their peers, Hank or Karen? (Note: In general, the lower the ERA, the better the pitcher.) Hank had an ERA with a z-score of Karen had an ERA with a z-score of (Round to two decimal places as needed.) Which player had a better year in comparison with their peers?According to the Bureau of Labor Statistics, the mean salary for registered nurses in Kentucky was $55,130. The distribution of salaries is assumed to be normally distributed with a standard deviation of $5,778. Someone would like to determine if registered nurses in Ohio have a greater average pay. To investigate this claim, a sample of 220 registered nurses is selected from the Ohio Board of Nursing, and each is asked their annual salary. The mean salary for this sample of 220 nurses is found to be $55,504.488. Completely describe the sampling distribution of the sample mean salary when samples of size 220 are selected. mean: μ x-bar = ____ standard deviation: σ x-bar = ____ shape: the distribution of is ____________(not normally distributed/normally distributed) because ___________ (the sample size is large/the sample size is not large/the population of salaries is normally distributed/the population of salaries is not normally distributed)