– 4x + 5 and Write an equation for a line perpendicular to y = passing through the point (-8,-3) y =

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
icon
Related questions
Question

Need help, please do it as showen in textbook

**Task: Find an Equation of a Perpendicular Line**

**Problem Statement:**

Write an equation for a line perpendicular to \( y = -4x + 5 \) and passing through the point \((-8, -3)\).

**Solution Steps:**

1. **Identify the Slope of the Given Line:**
   - The equation of the given line is \( y = -4x + 5 \), which is in slope-intercept form \( y = mx + b \).
   - The slope (\(m\)) of this line is \(-4\).

2. **Determine the Slope of the Perpendicular Line:**
   - The slope of a line perpendicular to another is the negative reciprocal.
   - Therefore, the slope of the line perpendicular to \( y = -4x + 5 \) is \(\frac{1}{4}\).

3. **Use the Point-Slope Form to Write the Equation:**
   - The point-slope form of a line is \( y - y_1 = m(x - x_1) \), where \( m \) is the slope, and \((x_1, y_1)\) is a point on the line.
   - Using the point \((-8, -3)\) and slope \(\frac{1}{4}\), the equation becomes:
     \[
     y - (-3) = \frac{1}{4}(x - (-8))
     \]
     \[
     y + 3 = \frac{1}{4}(x + 8)
     \]

4. **Simplify to Slope-Intercept Form \( y = mx + b \):**
   - Distribute the slope on the right side:
     \[
     y + 3 = \frac{1}{4}x + 2
     \]
   - Subtract 3 from both sides to solve for \( y \):
     \[
     y = \frac{1}{4}x + 2 - 3
     \]
     \[
     y = \frac{1}{4}x - 1
     \]

**Final Answer:**

The equation of the line perpendicular to \( y = -4x + 5 \) and passing through the point \((-8, -3)\) is:

\[
y = \frac{1}{4}x - 1
\]
Transcribed Image Text:**Task: Find an Equation of a Perpendicular Line** **Problem Statement:** Write an equation for a line perpendicular to \( y = -4x + 5 \) and passing through the point \((-8, -3)\). **Solution Steps:** 1. **Identify the Slope of the Given Line:** - The equation of the given line is \( y = -4x + 5 \), which is in slope-intercept form \( y = mx + b \). - The slope (\(m\)) of this line is \(-4\). 2. **Determine the Slope of the Perpendicular Line:** - The slope of a line perpendicular to another is the negative reciprocal. - Therefore, the slope of the line perpendicular to \( y = -4x + 5 \) is \(\frac{1}{4}\). 3. **Use the Point-Slope Form to Write the Equation:** - The point-slope form of a line is \( y - y_1 = m(x - x_1) \), where \( m \) is the slope, and \((x_1, y_1)\) is a point on the line. - Using the point \((-8, -3)\) and slope \(\frac{1}{4}\), the equation becomes: \[ y - (-3) = \frac{1}{4}(x - (-8)) \] \[ y + 3 = \frac{1}{4}(x + 8) \] 4. **Simplify to Slope-Intercept Form \( y = mx + b \):** - Distribute the slope on the right side: \[ y + 3 = \frac{1}{4}x + 2 \] - Subtract 3 from both sides to solve for \( y \): \[ y = \frac{1}{4}x + 2 - 3 \] \[ y = \frac{1}{4}x - 1 \] **Final Answer:** The equation of the line perpendicular to \( y = -4x + 5 \) and passing through the point \((-8, -3)\) is: \[ y = \frac{1}{4}x - 1 \]
Expert Solution
Step 1

Algebra homework question answer, step 1, image 1

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Recommended textbooks for you
Algebra and Trigonometry (6th Edition)
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:
9780134463216
Author:
Robert F. Blitzer
Publisher:
PEARSON
Contemporary Abstract Algebra
Contemporary Abstract Algebra
Algebra
ISBN:
9781305657960
Author:
Joseph Gallian
Publisher:
Cengage Learning
Linear Algebra: A Modern Introduction
Linear Algebra: A Modern Introduction
Algebra
ISBN:
9781285463247
Author:
David Poole
Publisher:
Cengage Learning
Algebra And Trigonometry (11th Edition)
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:
9780135163078
Author:
Michael Sullivan
Publisher:
PEARSON
Introduction to Linear Algebra, Fifth Edition
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:
9780980232776
Author:
Gilbert Strang
Publisher:
Wellesley-Cambridge Press
College Algebra (Collegiate Math)
College Algebra (Collegiate Math)
Algebra
ISBN:
9780077836344
Author:
Julie Miller, Donna Gerken
Publisher:
McGraw-Hill Education