Question is attached **Function Analysis and Midline Calculation****Function:**\[ Y = -8 \cos\left(6x + \frac{2\pi}{3}\right) + 4 \]**Question:**What is the midline of the function? Show your work and explain why.**Explanation:**The midline of a trigonometric function in the form of \( Y = A \cos(Bx + C) + D \) or \( Y = A \sin(Bx + C) + D \) is given by the value \( D \). This constant \( D \) shifts the graph vertically and represents the horizontal line around which the function oscillates.**Calculation:**In the given function:- The amplitude is \(-8\), which shows the maximum vertical distance from the midline.- The phase shift is determined by \(\frac{2\pi}{3}\), affecting the horizontal position of the graph.- The vertical shift, or midline, is represented by \(+4\).Therefore, the midline of the function is \( Y = 4 \).The midline \( Y = 4 \) is the central line around which the cosine function oscillates.

Name: Question is attached **Function Analysis and Midline Calculation****Fu
Uploaded: 2024-03-20T07:07:37.000Z
Channel: Bartleby
Description: Question is attached **Function Analysis and Midline Calculation****Function:**\[ Y = -8 \cos\left(6x + \frac{2\pi}{3}\right) + 4 \]**Question:**What is the midline of the function? Show your work and explain why.**Explanation:**The midline of a trig