4Ω ... 5/0° A ( -j22 j10 2 ll V3 20/90° V 8Ω -j2 2 ode 1: 11V1 + Y12V2 + Y13V3 = Isc1 pde 2: 21V1 + Y22V2 + Y23V3 = Isc2 ode 3: 1V1 + Y32V2 + Y33V3 = Isc3

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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hi! can you help me answer this in 6 decimal places?

Compose the nodal equations.
Multiply with the least common factor to remove fractions.
4Ω
...
V1
5/0° A (4
-j2 2
j10 2
ll
V2
Va
20/90° V
8 Ω
-j2 N
@node 1:
Y11V1 + Y12V2 + Y13V3 = Isc1
@node 2:
Y21V1 + Y22V2 + Y23V3 = Isc2
@node 3:
Y31V1 + Y32V2 + Y33V3 = Isc3
Transcribed Image Text:Compose the nodal equations. Multiply with the least common factor to remove fractions. 4Ω ... V1 5/0° A (4 -j2 2 j10 2 ll V2 Va 20/90° V 8 Ω -j2 N @node 1: Y11V1 + Y12V2 + Y13V3 = Isc1 @node 2: Y21V1 + Y22V2 + Y23V3 = Isc2 @node 3: Y31V1 + Y32V2 + Y33V3 = Isc3
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