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4a. Please help me solve this python programming. There are two parts to this problem. Include screenshots of your code for better understanding :)

4a. Please help me solve this python programming. There are two parts to this problem. Include screenshots of your code for better understanding :)

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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4a. Please help me solve this python programming. There are two parts to this problem. Include screenshots of your code for better understanding :)

Finally, add the following lines: from math import * x = sgrt (1 / 3) print (x) у %3D х * х * 3 print (y) * 3 z = x print (z) Again, the values of y and z, if we have no roundoff error, should be 1 in both cases. Are the values 1? Make a comment in your code answering the question. Was that surprising? You should have seen from those examples that sometimes we will encounter issues due to roundoff error and sometimes we won't. We can't always predict when roundoff error will be obvious. Part B: Tolerances for Comparisons. Add to your code from Part A the following lines to compare values of the variables b and e using the concept of tolerance: TOL = le-10 # check if b and e are equal within specified tolerance if abs (b e) < TOL: print ('b and e are equal within tolerance of', TOL) else: print ('b and e are NOT equal within tolerance of', TOL) Add a similar tolerance check to your code for y and z.
Transcribed Image Text:Finally, add the following lines: from math import * x = sgrt (1 / 3) print (x) у %3D х * х * 3 print (y) * 3 z = x print (z) Again, the values of y and z, if we have no roundoff error, should be 1 in both cases. Are the values 1? Make a comment in your code answering the question. Was that surprising? You should have seen from those examples that sometimes we will encounter issues due to roundoff error and sometimes we won't. We can't always predict when roundoff error will be obvious. Part B: Tolerances for Comparisons. Add to your code from Part A the following lines to compare values of the variables b and e using the concept of tolerance: TOL = le-10 # check if b and e are equal within specified tolerance if abs (b e) < TOL: print ('b and e are equal within tolerance of', TOL) else: print ('b and e are NOT equal within tolerance of', TOL) Add a similar tolerance check to your code for y and z.
Activity #1: Create a Python file named Lab4a_Act1.py for the following three-part activity. Please separate the various parts of your code with the following comment identifying the separate sections (copy/paste into your file with the appropriate letter). *## Part A ##: Part A: Identifying floating-point problems. First, type in and run the following program: a = 1 / 7 print (a) b = a * 7 print (b) Notice that the value of a is rounded off. The value of b, if we have no roundoff, should be 1. Is it? Make a comment in your code answering the question. Now add the following lines: C = 2 * a d = 5 * a e = c + d print (e) In this case, the value of e, if we have no roundoff, should be 1. Is it? Make a comment in your code answering the question.
Transcribed Image Text:Activity #1: Create a Python file named Lab4a_Act1.py for the following three-part activity. Please separate the various parts of your code with the following comment identifying the separate sections (copy/paste into your file with the appropriate letter). *## Part A ##: Part A: Identifying floating-point problems. First, type in and run the following program: a = 1 / 7 print (a) b = a * 7 print (b) Notice that the value of a is rounded off. The value of b, if we have no roundoff, should be 1. Is it? Make a comment in your code answering the question. Now add the following lines: C = 2 * a d = 5 * a e = c + d print (e) In this case, the value of e, if we have no roundoff, should be 1. Is it? Make a comment in your code answering the question.
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4a)

Code:

 

###########part A ############
a = 1/7 # 1/7 = 0.14285714285
print(a) #a is rounded off after 17 digits
b = a*7 #0.14258714285*7 = 1.0
print(b) # here b is 1 , it is computed like (1/7 )*( 7) = 1


c = 2*a # 2*(1/7) = 0.285714285
d = 5*a # 5*(1/7) = 0.714285714
e = c+d
print(e) #value of e is not 1 ,it has no roundoff

from math import *
x = sqrt(1/3)
print(x)#printing x
y = x*x*3 #value is 1 , like sqrt(x)*sqrt(x) = x, (1/3)*3 = 1
print(y)#printing y
z = x*3*x #it hs no roundoff
print(z)

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