48. A projectile is shot at a hill, the base of which is 300 m away. The projectile is shot at 60° above the horizontal with an initial speed of 75 m/s. The hill can be approximated by a plane sloped at 20° to the horizontal. Relative to the coordinate system shown in the following figure, the equation of this straight line is y = (tan20°) x - 109. Where on the hill does the projectile land?

48. A projectile is shot at a hill, the base of which is 300 m away. The projectile is shot at 60° above the horizontal with an initial speed of 75 m/s. The hill can be approximated by a plane sloped at 20° to the horizontal. Relative to the coordinate system shown in the following figure, the equation of this straight line is y = (tan20°) x - 109. Where on the hill does the projectile land?

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Principles of Physics: A Calculus-Based Text

5th Edition

ISBN:9781133104261

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter3: Motion In Two Dimensions

Section: Chapter Questions

Problem 16P: A firefighter, a distance d from a burning building, directs a stream of water from a fire hose at...

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University Physics 1 - Motion in 2D & 3D
I need help with this problem and a very detailed explanation of the solutions described below:

48. A projectile is shot at a hill, the base of which is 300 m away. The projectile is shot at 60° above the
horizontal with an initial speed of 75 m/s. The hill can be approximated by a plane sloped at 20° to the
horizontal. Relative to the coordinate system shown in the following figure, the equation of this straight line is
y = (tan20°) x - 109. Where on the hill does the projectile land?
y₁
75 m/s
60°
y = (tan 20°)x - 109
300 m-
20⁰
X

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