University Physics 1 - Motion in 2D & 3DI need help with this problem and a very detailed explanation of the solutions described below:& using this - general equation of height (y). 3) eliminate t from y using first equation x=V0Cos(Degree)t 4) Plug in given values 5) equate with given equation to find x , then find y 48. A projectile is shot at a hill, the base of which is 300 m away. The projectile is shot at 60° above thehorizontal with an initial speed of 75 m/s. The hill can be approximated by a plane sloped at 20° to thehorizontal. Relative to the coordinate system shown in the following figure, the equation of this straight line isy = (tan20°)x - 109. Where on the hill does the projectile land?y₁75 m/s60°y = (tan 20°)x - 109-300 m.20⁰X

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Description: University Physics 1 - Motion in 2D & 3DI need help with this problem and a very detailed explanation of the solutions described below:& using this - general equation of height (y). 3) eliminate t from y using first equation x=V0Cos(Degree)t 4) Plu

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College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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University Physics 1 - Motion in 2D & 3D
I need help with this problem and a very detailed explanation of the solutions described below:

& using this - general equation of height (y). 3) eliminate t from y using first equation x=V₀Cos(Degree)t 4) Plug in given values 5) equate with given equation to find x , then find y

48. A projectile is shot at a hill, the base of which is 300 m away. The projectile is shot at 60° above the
horizontal with an initial speed of 75 m/s. The hill can be approximated by a plane sloped at 20° to the
horizontal. Relative to the coordinate system shown in the following figure, the equation of this straight line is
y = (tan20°)x - 109. Where on the hill does the projectile land?
y₁
75 m/s
60°
y = (tan 20°)x - 109
-300 m.
20⁰
X

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