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47. There are two molecules with the formula C3H6. Propene, CH3CH=CH2, is the monomer of the polymer polypropylene, which is used for indoor-outdoor carpets. Cyclopropane is used as an anesthetic: CH: CH2 CH2 When heated to 499 °C, cyclopropane rearranges (isomerizes) and forms propene with a rate constant of 5.95 x 10 4 s-1. What is the half-life of this reaction? What fraction of the cyclopropane remains after 0.56 h(2016s) at 499.5 °C? [The unit of the provided rate constant indicates the reaction is first order.]

47. There are two molecules with the formula C3H6. Propene, CH3CH=CH2, is the monomer of the polymer polypropylene, which is used for indoor-outdoor carpets. Cyclopropane is used as an anesthetic: CH: CH2 CH2 When heated to 499 °C, cyclopropane rearranges (isomerizes) and forms propene with a rate constant of 5.95 x 10 4 s-1. What is the half-life of this reaction? What fraction of the cyclopropane remains after 0.56 h(2016s) at 499.5 °C? [The unit of the provided rate constant indicates the reaction is first order.]

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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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**Cyclopropane Isomerization and Its Use in Chemistry** **Chemical Context:** There are two molecules with the formula \( \text{C}_3\text{H}_6 \): 1. **Propene** (\( \text{CH}_3\text{CH}=\text{CH}_2 \)) – It is a monomer of the polymer polypropylene, which is used for indoor-outdoor carpets. 2. **Cyclopropane** – Cyclopropane is used as an anesthetic and can be represented structurally as a triangular ring of three carbon atoms, each bonded to two hydrogen atoms: \( \text{CH}_2 \) \ \ / \ \( \text{CH}_2 - \text{CH}_2 \) **Chemical Reaction:** When heated to \( 499 \, ^\circ\text{C} \), cyclopropane rearranges (isomerizes) and forms propene with a rate constant of \( 5.95 \times 10^{-4} \, \text{s}^{-1} \). **Questions:** 1. What is the half-life of this reaction? 2. What fraction of the cyclopropane remains after 0.56 hours (2016 seconds) at \( 499.5 \, ^\circ\text{C} \)? **Hint: The unit of the provided rate constant indicates the reaction is first order.** Choice: a. 0.30% remains **Periodic Table Reference:** The bottom part of the image shows an excerpt from the periodic table focusing on the elements in the f-block (lanthanides and actinides). - **Lanthanides** begin with **Lanthanum (La, atomic number 57)** and continue through **Lutetium (Lu, atomic number 71)**. - **Actinides** begin with **Actinium (Ac, atomic number 89)** and continue through **Lawrencium (Lr, atomic number 103)**. This segment of the periodic table is crucial because it highlights where the elements fit in the periodic arrangement and their relative atomic masses.
Transcribed Image Text:**Cyclopropane Isomerization and Its Use in Chemistry** **Chemical Context:** There are two molecules with the formula \( \text{C}_3\text{H}_6 \): 1. **Propene** (\( \text{CH}_3\text{CH}=\text{CH}_2 \)) – It is a monomer of the polymer polypropylene, which is used for indoor-outdoor carpets. 2. **Cyclopropane** – Cyclopropane is used as an anesthetic and can be represented structurally as a triangular ring of three carbon atoms, each bonded to two hydrogen atoms: \( \text{CH}_2 \) \ \ / \ \( \text{CH}_2 - \text{CH}_2 \) **Chemical Reaction:** When heated to \( 499 \, ^\circ\text{C} \), cyclopropane rearranges (isomerizes) and forms propene with a rate constant of \( 5.95 \times 10^{-4} \, \text{s}^{-1} \). **Questions:** 1. What is the half-life of this reaction? 2. What fraction of the cyclopropane remains after 0.56 hours (2016 seconds) at \( 499.5 \, ^\circ\text{C} \)? **Hint: The unit of the provided rate constant indicates the reaction is first order.** Choice: a. 0.30% remains **Periodic Table Reference:** The bottom part of the image shows an excerpt from the periodic table focusing on the elements in the f-block (lanthanides and actinides). - **Lanthanides** begin with **Lanthanum (La, atomic number 57)** and continue through **Lutetium (Lu, atomic number 71)**. - **Actinides** begin with **Actinium (Ac, atomic number 89)** and continue through **Lawrencium (Lr, atomic number 103)**. This segment of the periodic table is crucial because it highlights where the elements fit in the periodic arrangement and their relative atomic masses.
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