45kNCorresponding to Figurebelow, the loading on theportion AD of the beam willbeC1.25m3m0.75mB15kNUniformly distributed load ◎Cannot be said ○Uniformly varying load ◎Point loads O

Given shear force diagram, indicates simply supported beam with Uniformly distributed load on the…

Answered: 45kN Corresponding to Figure below, the…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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(a) For the cantilever beam shown in Figure Q1, 60 N 40 N/m 80 Nm 1m 1m 1m 1m Figure Q1 (i) write bending moment expression, M(x), using the Macauley's method determine the bending moment using M(x) for specified (ii) cross-sections at E, C and A (iii) justify the bending moment result calculated in (ii) for the free end of the beam at A (b) For a rectangular cross-section of width 100 mm and height 400 mm of a beam, the shear force is 2x106 N. Calculate the shear stress (t) at the following locations: (i) (ii) The top surface (iii) 60 mm from the top surface The neutral axis
please answer quickly
Draw shear force and bending moment diagrams P= 1000 N .w = 250 N/cm 5 cm 20 cm Figure 1.2 (not to scale)
Solve step by step in digitl format
Consider the beam in the picture below: 7kN/m 5kN/m P N/m Section 1 Section 2 Section 3 - L/3 L/3 L/3 %3D Take P = the last four digits of your student number in N/m. If P<250 N/m then take P = 30OON/m instead. Take L = the third digit of your student number, reading left to reight. If this value is zero then take L = 2 Assume: The reaction at the Pin = V pin 47000L+9PL )N 54 The reaction at the Roller = Vroller = 61000L+9PL 54 and that both reactions act vertically upwards. a) Find an expression for the internal moment for Section 1. Show all working and any relevant free body diagrams. b) What is the maximum magnitude of the internal moment for Section 1? Mark sure you prove that the value you calculate is the maximum. c) Find an expression for the internal moment for Section 2. Show all working and any relevant free body diagrams. d) What is the maximum magnitude of the internal moment for Section 2? Mark sure you prove that the value you calculate is the maximum. e) Find an…
Question 2. A X Given, B RD: 8.75 C F₂ The above figure (not drawn to scale) shows a 6 m long beam subjected to forces F₁, and F₂. KN D »I»I»E F₁ = 80 kN, F₂ = 50 kN Length X = 2 m, Length Y = 1.5 m Calculate RB and Rp, the vertical reaction forces at the supports, B and D respectively. Enter your answers in kilonewtons (kN) in the boxes below: RB: 101.25 kN
In Figure Q4a, AC is a beam is supported at A and C with a uniformly distributed load of 40 kN/m between A and B. The distance A to B is d₁ with a length of 12.00 m; the distance B to C is d₂ with a length of 6.00 m. The point M is located at the mid-point of the beam AC. A UDL C d1 M B d2 Figure Q4a a) Draw and label the shear force diagram (SFD) for the beam shown in Figure Q4a. Label the values for shear force and bending moment at points A, B, C and at the mid-point M. [7 marks] b) Draw and label the bending moment diagram (BMD) for the beam shown in Figure Q4a and clearly indicate the type of bending that occurs between AB and between BC. On your diagram, clearly show the value of the maximum bending moment and where it occurs along the beam terms of the distance from A. In addition, label the values for bending moment at points A, B, C and at the mid-point M. [8 marks] c) The diameter (d) of a solid rod (i.e., with a circular cross-section) is 14 mm and is made from a homogeneous…
7 The Questions Question 4. X Given, B cere RD 26.25 C F = 90 kN, UDL = 40 kN/m UDL The above figure (not drawn to scale) shows a 6 m long beam subjected to a force F and a uniformly distributed load UDL. kN D 補 I»I»I»] Length X = 2m, Length Y= 0.5 m Calculate RB and RD, the vertical reaction forces at the supports. Enter your answers in kilonewtons (kN), correct to 3 decimal places, in the boxes below. RB

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45kN Corresponding to Figure below, the loading on the portion AD of the beam will be C 1.25m 3m 0.75m B 15kN Uniformly distributed load ◎ Cannot be said ○ Uniformly varying load ◎ Point loads O