45. A solution in which equilibrium exists between undissolved anddissolved solute is always *4NH3(g) + 502(g) = 4N0(g) + 6H20(g)[NO]*[H20]°(NH3]* [02][NO]*+[H20]6[NH3]* +[02]°a. Keq =b. K =a.[4NO][6H20]d. Ka =[4NO]+[6H20]c. Keq =[4NH3]+[502]%3D[4NH 3][502)

The equilibrium constant can be defined as the product of molar concentration of product species…

45. A solution in which equilibrium exists betwoen undissolved and dissolved solute is always 4NH3(g) + 50z(g)=4N0(g) + 6H20(g) a. Keq = [NO]*(H20]6 [NO]*+[H20]6 [NH3]* +[O2]° b. K = %3D [NH3]* [02] Ob. a. [4NO][6H20] (4NH 3][502) [4N0]+[6H20] [4NH3]+[502] c. Keq d. K = %3D

45. A solution in which equilibrium exists betwoen undissolved and dissolved solute is always 4NH3(g) + 50z(g)=4N0(g) + 6H20(g) a. Keq = [NO](H20]6 [NO]+[H20]6 [NH3]* +[O2]° b. K = %3D [NH3]* [02] Ob. a. [4NO][6H20] (4NH 3][502) [4N0]+[6H20] [4NH3]+[502] c. Keq d. K = %3D

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

45. A solution in which equilibrium exists between undissolved and
dissolved solute is always *
4NH3(g) + 502(g) = 4N0(g) + 6H20(g)
[NO]*[H20]°
(NH3]* [02]
[NO]*+[H20]6
[NH3]* +[02]°
a. Keq =
b. K =
a.
[4NO][6H20]
d. Ka =
[4NO]+[6H20]
c. Keq =
[4NH3]+[502]
%3D
[4NH 3][502)

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