45. A solution in which equilibrium exists betwoen undissolved and dissolved solute is always 4NH3(g) + 50z(g)=4N0(g) + 6H20(g) a. Keq = [NO]*(H20]6 [NO]*+[H20]6 [NH3]* +[O2]° b. K = %3D [NH3]* [02] Ob. a. [4NO][6H20] (4NH 3][502) [4N0]+[6H20] [4NH3]+[502] c. Keq d. K = %3D
45. A solution in which equilibrium exists betwoen undissolved and dissolved solute is always 4NH3(g) + 50z(g)=4N0(g) + 6H20(g) a. Keq = [NO]*(H20]6 [NO]*+[H20]6 [NH3]* +[O2]° b. K = %3D [NH3]* [02] Ob. a. [4NO][6H20] (4NH 3][502) [4N0]+[6H20] [4NH3]+[502] c. Keq d. K = %3D
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![45. A solution in which equilibrium exists between undissolved and
dissolved solute is always *
4NH3(g) + 502(g) = 4N0(g) + 6H20(g)
[NO]*[H20]°
(NH3]* [02]
[NO]*+[H20]6
[NH3]* +[02]°
a. Keq =
b. K =
a.
[4NO][6H20]
d. Ka =
[4NO]+[6H20]
c. Keq =
[4NH3]+[502]
%3D
[4NH 3][502)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F504dad56-f4b5-4078-80ed-5675ba124bfe%2F9ce74742-0828-4ffe-ae35-df5ac714efda%2Fa9tqe2o_processed.png&w=3840&q=75)
Transcribed Image Text:45. A solution in which equilibrium exists between undissolved and
dissolved solute is always *
4NH3(g) + 502(g) = 4N0(g) + 6H20(g)
[NO]*[H20]°
(NH3]* [02]
[NO]*+[H20]6
[NH3]* +[02]°
a. Keq =
b. K =
a.
[4NO][6H20]
d. Ka =
[4NO]+[6H20]
c. Keq =
[4NH3]+[502]
%3D
[4NH 3][502)
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