Answered: 45° 10 m- A = 2 m/s₂ aA=3 m/s² 45°… | bartleby

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45°
10 m
VA= 2 m/s,
aA=3 m/s²
45°
Given: Point A on rod AB has an
acceleration of 3 m/s² and
a velocity of 2 m/s at the
instant the rod becomes
horizontal.
Find: The angular acceleration
of the rod at this instant.

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