**Problem 44**: An L4×3×3/4 is attached to a gusset plate with three 3/4 in. bolts spaced at 3 in., with an end and edge distance of 1.5 in. as shown in Figure P4.44. Determine the available block shear strength of the A36 angle by (a) LRFD and (b) ASD.**Figure P4.44 Description**:The figure illustrates an L-shaped angle iron attached to a gusset plate. There are three labeled circular holes representing bolts. The dimensions include:- Vertical dimension from the top to bottom of the angle is 3 in.- Horizontal length between the centers of the bolt holes is 3 in. each.- End and edge distances from the bolt center to the edge are 1.5 in.- The height from the top edge of the L-shape to the first bolt hole is 1.5 in.This setup is used to calculate the block shear strength of an A36 steel angle using two methods: Load and Resistance Factor Design (LRFD) and Allowable Stress Design (ASD).

Answered: Image /qna-images/answer/9328eed3-fb72-462c-a940-8b9bbcd40a77.jpg

44. An L4×3×3/4 is attached to a gusset plate with three 3/4 in. bolts spaced at 3 in. with an end and edge distance of 1.5 in. as shown in Figure P4.44. Determine the available block shear strength of the A36 angle by (a) LRFD and (b) ASD.

44. An L4×3×3/4 is attached to a gusset plate with three 3/4 in. bolts spaced at 3 in. with an end and edge distance of 1.5 in. as shown in Figure P4.44. Determine the available block shear strength of the A36 angle by (a) LRFD and (b) ASD.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

The T-shape shown in the figure is used as a tension member. Given that the gross area Ag = 2556 mm², tw = 10 mm, gross depth d = 220 mm and bolts are 16-mm-diameter, with Fy=345 MPa and Fu = 450 MPa, calculate the nominal block shear strength for combined tensile rupture and shear rupture. Write your answer to the nearest whole number in kN. Consider Ubs = 1.0 T 40 mm. +* 125 mm O 4@.75 mm O O O O
Please show solutions on how to get the 2 and 1 value. The circle green in the figure. Civil engineering- steel design
SITUATION I A lapped bolted lension member is shown. Diameter of bolts are 22 mm and the plate material is A36 steel Fy = 275 MPа, Fи 3 415 МPа. Assume the fasteners are adequate and do not control the tensile capacity. Diameter of hole is 2.5 mm bigger than the diameter of bolt. 12 :: 350 50 100 100 50 50 1. Determine the tensile capacity of the lapped joint based on gross area. a. 252.656 kN c. 866.250 kN b. 202.125 kN d. 693.000 kN 2. Determine the net Area for the tensile capacity of the lapped joint. а. 3318 тm? c. 5250 mm? b. 1554 mm? d. 1824 mm? 3. Determine the tensile capacity of the lapped joint based on the net area. a. 752.856 kN C. 866.250 kN b. 688.845 kN d. 1039.500 kN
PL 5/8 x 12 3/4-in-diameter bolts
A double-angle shape, 2L7 3 4 3 3⁄8, is used as a tension member. The twoangles are connected to a gusset plate with 7⁄8-inch-diameter bolts throughthe 7-inch legs, as shown in Figure P3.4-5. A572 Grade 50 steel is used.a. Compute the design strength.b. Compute the allowable strength.
SHOW COMPLETE SOLUTION AND DRAW ILLUSTRATION
The tension member shown in the figure is connected to a gusset plate as shown with 1.210-inch diameter bolts. It is subjected to the dead and live loads as shown. Take Fy = 33.29 ksi and Fu = 52.93 ksi. Assume Ae = An. a) Draw the critical cross-section and show its dimensions using your data. b) Determine whether this member has enough strength using LRFD and the critical ASCE 7 loading combination.
1. The tension member shown in Figure 3.4-2 is a PL 58 x 10, and the steel is A36. The bolts are 3/4-inch in diameter. a. Draw the different potential failure lines. b. Compute the effective net area. 22" 2½" 2" 4 3" *₁ 3" ✓ 2" 2. A double-channel shape, 2C10 x 20 steel, Fy = 50 ksi and Fu = 70 ksi, is used for a built-up tension member as shown in the figure. The holes are for 12-inch-diameter bolts. PNA a. Determine the design strength for LRFD. b. Determine the allowable strength for ASD. YD Shape A 2" 2" -X Area, Depth, d | 3²²-|-1 3²² | 00 "There is no elevator to success, you have to take the stairs." - Zig Ziglar God bless. Ⓒ O O O Web Thickness, tw in. in. O 4" C10-30 x25 x20 5.87 10.0 10 0.379 % x15.3 4.48 10.0 10 0.240 4 4" Table 1-5 C-Shapes Dimensions Flange Width, b₁ 2 in. in. in.2 in. C15x50 14.7 15.0 15 0.716 1168 3.72 3% 0.650 % x40 11.8 15.0 15 0.520 x33.9 10.0 15.0 15 0.400 % 14 3.52 32 0.650 % %/16 3.40 3% 0.650 % C12-30 8.81 12.0 12 0.510 4 3.17 3% x25 7.34 12.0 12…
5 please help meee
The tension member shown in Figure 3.4-2 is a PL 5/8 x 10, and the steel is A36. The bolts are 7/8-inch in diameter. a. Determine the design strength for LRFD. b. Determine the allowable strength for ASD. | 2" +|+| in seinefrinehich 9 оо SO
7. Determine the design tensile strength of the plate (200 x 10 mm) connected to 12 mm thick gusset, using 24 mm bolts as shown below. Use A572M Grade 345 steel materials. 200 40 50 40 30 30 30 30 40
A double-angle shape is shown in the figure. The steel is A36, and the holes are for 1/2-inch-diameter bolts. Assume the Ae = 0.75An. Section 2L5 x 3 x16 LLBB Determine the allowable tensile strength for ASD. Select one: а. 52.1 b. 104.2 c. 87.8 d. 43.9