424.6755m/so 20,C1s. 4 A football is kicked such that it reaches a maximurm height of 15 m and returns to the ground. It travels a forward distance of 40 m. a) What is the initial speed of the projectile? V28hmax 4. b) 0- 56.3) b) What is the initial angle? hmax = Vo Sen'o Yo

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Chapter1: Units, Trigonometry. And Vectors
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vo= 424.6755m/s20.6m1S-
4 A football is kicked such that it reaches a maximum height of 15 m and returns to the ground. It travels
a forward distance of 40 m.
rnf 12.5 m/s and a vertical velocity of 40 m/s when
Vo= 424.6755m/s 20.Cm1S.
AA football is kicked such that it reaches a maximum height of 15 m and returns to the ground.
a) What is the initial speed of the projectile?
4. b) 0 = 56.3°)
V=2ghmak,
b) What is the initial angle?
hmax = Vo Sento
Sune
2x9.8m3x1s
(gm(SC.3099)1
tau@<1,5, B=tanli.s 94m's
0.83205)2
294 m2!s
DI6923
tang=4x15mGom
Yo
28
%3D
40m
40
0m
hamar no = 56,309 5613
5. In the Olympic shotput event, an athlete throws the shot with an initial speed of 12.0 m/s at
a 40.0° angle from the horizontal. The shot leaves her hand at a height of at y 1.80 m above the ground.
The shot lands at y = 0.
a) What is the time for the upward part of the motion only?
b) What is the maximum height of the shot relative to the ground?
c) What is the flight time?
d) How far does the shot travel?
5. a) 0.787 sec b) 4.84 m c) 1.780 sec d)16.36 m
Transcribed Image Text:vo= 424.6755m/s20.6m1S- 4 A football is kicked such that it reaches a maximum height of 15 m and returns to the ground. It travels a forward distance of 40 m. rnf 12.5 m/s and a vertical velocity of 40 m/s when Vo= 424.6755m/s 20.Cm1S. AA football is kicked such that it reaches a maximum height of 15 m and returns to the ground. a) What is the initial speed of the projectile? 4. b) 0 = 56.3°) V=2ghmak, b) What is the initial angle? hmax = Vo Sento Sune 2x9.8m3x1s (gm(SC.3099)1 tau@<1,5, B=tanli.s 94m's 0.83205)2 294 m2!s DI6923 tang=4x15mGom Yo 28 %3D 40m 40 0m hamar no = 56,309 5613 5. In the Olympic shotput event, an athlete throws the shot with an initial speed of 12.0 m/s at a 40.0° angle from the horizontal. The shot leaves her hand at a height of at y 1.80 m above the ground. The shot lands at y = 0. a) What is the time for the upward part of the motion only? b) What is the maximum height of the shot relative to the ground? c) What is the flight time? d) How far does the shot travel? 5. a) 0.787 sec b) 4.84 m c) 1.780 sec d)16.36 m
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