7. A bullet is fired downward at an angle of 30° below the horizontal. 3.20 seconds later, the bullet hits a target that is 120 m horizontally to the right of the starting point. Let x direction be to the right and y direction point upward. a) Find vox, the x-component of the initial velocity of the bullet. b) Find voy, the y-component of the initial velocity of the bullet.
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- 1. Two projectiles, both with a velocity of 50 m/s, are thrown from the same spot. One of them is thrown with an angle of 60 degrees, and the other one is thrown with an angle of 45 degrees. However, they both land on the same spot on top of a brick wall. How high is the brick wall?Find the impact velocity of the ball and verify if it is a homerun. Use PARAMETRIC EQUATIONS and make a graph of the trajectory of the ball.What do you need in order to determine the initial velocity of a projectile fired horizontally?
- Cedar has been trying to get Liam's attention for weeks. He decides to make a paper airplane to hit Liam in the back of his head (and grab his attention). If the paper airplane flies 2.64 m [W 26˚ N] and then is caught by the wind, which causes it to travel 3.21 m [S 12˚ E]. What is the paper airplane's total displacement? (please hand-write it and make it clear)9. If a projectile (such as a bullet) is fired into the air with an initial velocity v at an angle of elevation of θ (see the figure), then the height h of the projectile at time t is given by24. A shell is fired with a horizontal velocity in the positive x direction at a speed of 330 m/s from the top of an 80- m high cliff. The shell strikes the ground 1330 m from the base of the cliff. What is the magnitude of the velocity of the shell as it hits the ground? Hint: you need to determine horizontal and vertical components of the final velocity first, from the kinematic equations, then calculate magnitude of the velocity. While the horizontal velocity remains constant, the vertical velocity does not. You will need time of flight to determine the latter. 80 m 1330 m A) 4.0 m/s B) 9.8 m/s B) 9.8 m/s C) 82 m/s D) 170 m/s (E) 332 m/s
- When there is no air resistance what best describes the vectors of a projectile in motion: a.The acceleration vector and velocity vector are both constant magnitude. b.The acceleration vector is constant magnitude and perpendicular to the trajectory. The velocity vector is at a tangent to the trajectory c.The acceleration vector is constant and points straight down. The velocity vector is perpendicular to the trajectory d.The acceleration vector is constant and points straight down. The velocity vector is at a tangent to the trajectoryProfessional golfers can drive the ball over 200 m. While air resistance is significant, its effects are nearly canceled because lift is gained from backspin on the ball, and so a reasonable description of the ball’s trajectory is obtained if air resistance is neglected. Suppose a golfer hits a ball 200 m on level ground, giving it an initial velocity at an angle of 45o. The duration of the impact of the club and ball has been measured to be 1.00 ms. a) Calculate the velocity of the ball just after it is struck b) What is the 0.0450 kg ball's change in momentum?A ball is thrown at an initial height of 65 feet at an initial velocity of 75 feet/second at an angle of 65 degrees. Given the parametric equations yY = - - 16t + Vo · Sin(0)t + ho and x = Vo Cos(0)t. When doing calculations, carry 5 digits of accuracy, so your round off does not build up. a. What is the ball's height in 3 seconds? feet. seconds. b. When will the object hit the ground? feet. c. How far horizontally will the ball be when it hits the ground? seconds. d. When will the ball be at its maximum height? e. What is the ball's maximum height? feet. feet f. How far horizontally will the ball be when it reaches its maximum height?
- Table 1. Shot velocity (V) of the projectile at an angle of 30. Two shots were made for each distance. Column 1 and 2 correspond to the throw from 1 meter away. To determine the velocity of fire of the projectile on the x-axis, use the equation: Vxo = Vo * cos 30°.A catfish is spotted at the bottom of a creek. The depth of the water is 2 m. A hunter (with no knowledge ofoptics) fires a rifle shot, directly aimed at the catfish. The bullet strikes the water at an angle of 40° to the water. Assumethat the bullet is not deflected by the air/water interface, what is the distance from the bullet hole at the bottom of the creekto the catfish?A) 0.88 mB) 0.97 mC) 0.49 mD) 0.56 mE) 0.73 ma. Find the Range and Maximum Height of a projectile launched at 4.5 m/s t an angle of 300. Find the Range and Maximum Height of a projectile launched at 4.5 m/s t an angle of 600. Discuss any similarities between a. and b.