42. Nylon bars were tested for brittleness (Bennett and Franklin 1954). Each of 280 bars was molded under similar conditions and was tested in five places. Assuming that each bar has uniform composition, the number of breaks on agiven bar should be binomially distributed with five trials and an unknown probability p of failure. If the bars are all of the same uniform strength, p should be the same for all of them; if they are of different strengths, p should vary from bar to bar. Thus, the null hypothesis is that the p's are all equal. The following table summarizes the outcome of the experiment: Breaks/Bar Freuency 157 69 35 17 0 4 a. Under the given assumption, the data in the table consist of 280 observations of independent binomial random variables. Find the mle of p. b. Pooling the last three cells, test the agreement of the observed frequency distribution with the binomial distribution using Pearson's chi-square test.

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42. Nylon bars were tested for brittleness (Bennett and Franklin 1954). Each of 280
bars was molded under similar conditions and was tested in five places. Assuming
that each bar has uniform composition, the number of breaks on agiven bar should
be binomially distributed with five trials and an unknown probability p of failure.
If the bars are all of the same uniform strength, p should be the same for all of
them; if they are of different strengths, p should vary from bar to bar. Thus, the
null hypothesis is that the p's are all equal. The following table summarizes the
outcome of the experiment:
Breaks/Bar Freuency
157
69
35
17
0
4
a. Under the given assumption, the data in the table consist of 280 observations
of independent binomial random variables. Find the mle of p.
b. Pooling the last three cells, test the agreement of the observed frequency
distribution with the binomial distribution using Pearson's chi-square test.
Transcribed Image Text:42. Nylon bars were tested for brittleness (Bennett and Franklin 1954). Each of 280 bars was molded under similar conditions and was tested in five places. Assuming that each bar has uniform composition, the number of breaks on agiven bar should be binomially distributed with five trials and an unknown probability p of failure. If the bars are all of the same uniform strength, p should be the same for all of them; if they are of different strengths, p should vary from bar to bar. Thus, the null hypothesis is that the p's are all equal. The following table summarizes the outcome of the experiment: Breaks/Bar Freuency 157 69 35 17 0 4 a. Under the given assumption, the data in the table consist of 280 observations of independent binomial random variables. Find the mle of p. b. Pooling the last three cells, test the agreement of the observed frequency distribution with the binomial distribution using Pearson's chi-square test.
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