41) The table lists the sugar content of two types of apples from three different orchards. Ata 0.05, test the claim that the sugar content of the apples and the orchard where they41)1were grown are not related.Sugar ContentApple Type 1Orchard 1Orchard 2Orchard 343731Apple Type 2A) There is not evidence to reject the claim that the sugar content of the apple type and19the orchard number are not related because the test value 1.375< 12.592B) There is evidence to reject the claim that the sugar content of the apple type and theorchard number are not related because the test value 5.991 > 2.625C There is evidence to reject the claim that the sugar content of the apple type and theorchard number are not related because the test value 12.592 > 1.375D) There is not evidence to reject the claim that the sugar content of the apple type andthe orchard number are not related because the test value 2.625 < 5.99 1

The null and alternative hypotheses areH0: Sugar content of the apple type and the orchard number…

Answered: 41) The table lists the sugar content…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A1) - Calculate the mean speed [in mph] of 4 cars travelling at 46 mph and 4 cars travelling at 63 mph. A2) Calculate the root mean square speed [in mph] of 6 cars travelling at 43 mph and 7 cars travelling at 56 mph. Sidenote: for a1 I tried submitting the answer as 54.5 and it was wrong for a2 I tried submitting the answer as 50.42 and it was incorrect
ata Set 12 “Passive and Active Smoke” in Appendix B includes cotinine levels measured in a group of nonsmokers exposed to tobacco smoke (n = 40, Mean = 60.58 ng>mL, s = 138.08 ng>mL) and a group of nonsmokers not exposed to tobacco smoke (n = 40, Mean = 16.35 ng>mL, s = 62.53 ng>mL). Cotinine is a metabolite of nicotine, meaning that when nicotine is absorbed by the body, cotinine is produced. Use a 0.05 significance level to test the claim that nonsmokers exposed to tobacco smoke have a higher mean cotinine level than nonsmokers not exposed to tobacco smoke. 1. Find the degrees of freedom using the conversative estimate formula. What is it? 2. Find the critical value. What is it? 3. Sketch a normal distribution curve and highlight the region of significance.
15. Research results suggest that IQ scores for boys Plomin, 2006). A typical study looking at 10-year-old are more variable than IQ scores for girls (Arden & size would be reported in a journal article. children classifies participants by gender and by low. average, or high IQ. Following are representing the research results. Do the data indicate a significant difference between the frequency distri- butions for males and females? Test at the .05 level of significance and describe the difference. hypothetical data 1 IQ Low Average High Вoys 18 42 20 80 Girls 12 54 14 80 n = 160 Int Ava
Answer the whole quesrion
Express the alternative hypothesis in symbolic form. A psychologist claims that the mean amount of time (in hours) that females spend in talk therapy is more than that of men. Assume that two samples are independent. Let the female talk therapy times be the first population and the male talk therapy times be the second population.
To test whether the mean time needed to mix a batch of material is the same for machines produced by three manufacturers, the Jacobs Chemical Company obtained the following data on the time (in minutes) needed to mix the material. Compute the values below (to 2 decimals, if necessary). Sum of Squares, Treatment Sum of Squares, Error Mean Squares, Treatment Mean Squares, Error Calculate the value of the test statistic (to 2 decimals). 1 19 25 23 21 Manufacturer a. Use these data to test whether the population mean times for mixing a batch of material differ for the three manufacturers. Use a = 0.05. What conclusion can you draw after carrying out this test? - Select your answer - 2 30 28 33 29 3 21 20 24 23 The p-value is - Select your answer - V What is your conclusion? - Select your answer - b. At the a= 0.05 level of significance, use Fisher's LSD procedure to test for the equality of the means for manufacturers 1 and 3. Calculate Fisher's LSD Value (to 2 decimals).

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