40VⒸ 140V 1 120 250 5A www 200 400 3 2 400 7.5A

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Tried to find v1, v2 v3 by using the nodel analysis but I didn't get the same value, could you explain mathematically step by step, how v1= -10 and v2= 132 and v3= -84
40v
V1 +40
12
V3
40
140V
[V2 V1]
20
+
www
+
120
V1
25
1
- 5+
V3 - V2
40
250
5A
200
400
V1 V2
20
V2 - V1
40
+7.5 = 0
3
2
400
+ 5 = 0
+-7.5=0
17.5A
Solving, v₁ = -10 V; 2 = 132 V; V3 = -84 V; 140V =
-
O
-10 + 40
+2
12
= 2.5 A
Transcribed Image Text:40v V1 +40 12 V3 40 140V [V2 V1] 20 + www + 120 V1 25 1 - 5+ V3 - V2 40 250 5A 200 400 V1 V2 20 V2 - V1 40 +7.5 = 0 3 2 400 + 5 = 0 +-7.5=0 17.5A Solving, v₁ = -10 V; 2 = 132 V; V3 = -84 V; 140V = - O -10 + 40 +2 12 = 2.5 A
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