4000 100 80 60 40 IR Spectrum (liquid film) % of base peak C-A 3000 43 10 40 13C NMR Spectrum (100 MHz, CDCI, solution) DEPT CH, CH, CH M = 86 80 proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 9 8 ww 1716 1200 800 1600 V (cm¹) Mass Spectrum 2000 120 160 m/e 160 7 200 120 6 240 C4H602 280 5 solvent 80 4 Problem 6 حلتك او " بلون 2 UV Spectrum max 289 nm (log, 1.4) solvent methanol گرد 40 3 200 3 2-4 2 112 8 (ppm) TI 1

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Chapter1: Chemical Foundations
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What is the IR and HNMRAndCNMR and mass in this example explain the chemical shift
4000
100
IR Spectrum
(liquid film)
80
60
% of base peak
C-A
3000
43
10
40
13C NMR Spectrum
(100 MHz, CDCI, solution)
DEPT CH₂ CH₂ CH4
M+* = 86
80
proton decoupled
200
¹H NMR Spectrum
(200 MHz, CDCI, solution)
9
8
m
1716
1200
1600
V (cm¹)
2000
120
160
m/e
160
7
200 240
120
800
Mass Spectrum
6
C4H602
280
5
solvent
+
80
4
Problem 6
حلقات او )
لون
2
UV Spectrum
max 289 nm (log, 1.4)
solvent methanol
40 30 20
2
1
3
کرد
2-4
112
8 (ppm)
8
Transcribed Image Text:4000 100 IR Spectrum (liquid film) 80 60 % of base peak C-A 3000 43 10 40 13C NMR Spectrum (100 MHz, CDCI, solution) DEPT CH₂ CH₂ CH4 M+* = 86 80 proton decoupled 200 ¹H NMR Spectrum (200 MHz, CDCI, solution) 9 8 m 1716 1200 1600 V (cm¹) 2000 120 160 m/e 160 7 200 240 120 800 Mass Spectrum 6 C4H602 280 5 solvent + 80 4 Problem 6 حلقات او ) لون 2 UV Spectrum max 289 nm (log, 1.4) solvent methanol 40 30 20 2 1 3 کرد 2-4 112 8 (ppm) 8
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