400 N/m The element is supported by a Pin Connection at A and a trolley at B. Define force directions with arrows for all problems. (a) Calculate the magnitude and direction of the vertical reaction at B. 6 m 600 N/m 400 N/m B (b) Calculate the magnitude and direction of the vertical component of the reaction at A. -6 m- -6 m (c) Calculate the magnitude and direction of the horizontal component of the reaction at A.
400 N/m The element is supported by a Pin Connection at A and a trolley at B. Define force directions with arrows for all problems. (a) Calculate the magnitude and direction of the vertical reaction at B. 6 m 600 N/m 400 N/m B (b) Calculate the magnitude and direction of the vertical component of the reaction at A. -6 m- -6 m (c) Calculate the magnitude and direction of the horizontal component of the reaction at A.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:### Problem Description
The element is supported by a **Pin Connection** at point **A** and a **trolley** at point **B**. Define force directions with arrows for all problems.
### Task
1. **Calculate the magnitude and direction of the vertical reaction at B.**
2. **Calculate the magnitude and direction of the vertical component of the reaction at A.**
3. **Calculate the magnitude and direction of the horizontal component of the reaction at A.**
### Diagram Explanation
The diagram illustrates a structural element subjected to various forces:
- **Distributed Load**: There are triangular and rectangular distributed loads applied on the structure. The triangular load starts at 400 N/m, increasing along a 6 m span. The rectangular load is constant at 400 N/m over another 6 m span following the triangular distribution.
- **Distances**: The entire element is 18 m long, divided into three sections of 6 m each.
- **Support Points**:
- **Point A**: This is a pin connection allowing rotation but restricting translation in both horizontal and vertical directions.
- **Point B**: This includes a trolley which allows movement in the horizontal direction but no vertical movement.
The goal is to resolve the forces at points A and B due to the distributed loads.
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