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40) For a reaction between a thiolate anion and 1-Chloropropane, why is SN2 more favoured than E2 reaction at normal room temperatures? a. Because it yields Zaitsev's product which is more stable then the substituted product. b. Because the substituted product has a stable intermediate. c. Because it takes less amount of energy spent to undergo a nucleophilic attack towards the partially positive alpha carbon and eliminate the leaving group; than to abstract an anti-periplanar proton and form a double bond after the leaving group departs. d. Because the leaving groups of alkyl halides in an SN2 reaction are better leaving groups than E2 substrate leaving groups; thus, less energy is required for SN2 to occur. e. Because it takes less amount of energy spent for a good nucleophile to attack the alpha carbon and eliminate the leaving group than for a weak base to abstract an anti-periplanar proton and form a double bond after eliminating the leaving group. f. Both C & E.

40) For a reaction between a thiolate anion and 1-Chloropropane, why is SN2 more favoured than E2 reaction at normal room temperatures? a. Because it yields Zaitsev's product which is more stable then the substituted product. b. Because the substituted product has a stable intermediate. c. Because it takes less amount of energy spent to undergo a nucleophilic attack towards the partially positive alpha carbon and eliminate the leaving group; than to abstract an anti-periplanar proton and form a double bond after the leaving group departs. d. Because the leaving groups of alkyl halides in an SN2 reaction are better leaving groups than E2 substrate leaving groups; thus, less energy is required for SN2 to occur. e. Because it takes less amount of energy spent for a good nucleophile to attack the alpha carbon and eliminate the leaving group than for a weak base to abstract an anti-periplanar proton and form a double bond after eliminating the leaving group. f. Both C & E.

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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40) For a reaction between a thiolate anion and 1-Chloropropane, why is SN2 more favoured than E2 reaction at normal room temperatures? a. Because it yields Zaitsev's product which is more stable then the substituted product. b. Because the substituted product has a stable intermediate. c. Because it takes less amount of energy spent to undergo a nucleophilic attack towards the partially positive alpha carbon and eliminate the leaving group; than to abstract an anti-periplanar proton and form a double bond after the leaving group departs. d. Because the leaving groups of alkyl halides in an SN2 reaction are better leaving groups than E2 substrate leaving groups; thus, less energy is required for SN2 to occur. e. Because it takes less amount of energy spent for a good nucleophile to attack the alpha carbon and eliminate the leaving group than for a weak base to abstract an anti-periplanar proton and form a double bond after eliminating the leaving group. f. Both C & E.
Transcribed Image Text:40) For a reaction between a thiolate anion and 1-Chloropropane, why is SN2 more favoured than E2 reaction at normal room temperatures? a. Because it yields Zaitsev's product which is more stable then the substituted product. b. Because the substituted product has a stable intermediate. c. Because it takes less amount of energy spent to undergo a nucleophilic attack towards the partially positive alpha carbon and eliminate the leaving group; than to abstract an anti-periplanar proton and form a double bond after the leaving group departs. d. Because the leaving groups of alkyl halides in an SN2 reaction are better leaving groups than E2 substrate leaving groups; thus, less energy is required for SN2 to occur. e. Because it takes less amount of energy spent for a good nucleophile to attack the alpha carbon and eliminate the leaving group than for a weak base to abstract an anti-periplanar proton and form a double bond after eliminating the leaving group. f. Both C & E.
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