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40 6. Instead of using kinematics, if you use dynamics (Newton's second law), the acceleration of the masses in the Atwood's machine can be calculated as: where m is the hanging mass, M is the mass of the system (the red tool box), and g 9.80 m/s² is the acceleration due to gravity. What is the system mass M when a 0.33 m/s² and the hanging mass is m = 0.020 kg? M-0.400 kg a= M-0.660 kg M 0.380 kg M-0.574 kg M 0.286 kg

40 6. Instead of using kinematics, if you use dynamics (Newton's second law), the acceleration of the masses in the Atwood's machine can be calculated as: where m is the hanging mass, M is the mass of the system (the red tool box), and g 9.80 m/s² is the acceleration due to gravity. What is the system mass M when a 0.33 m/s² and the hanging mass is m = 0.020 kg? M-0.400 kg a= M-0.660 kg M 0.380 kg M-0.574 kg M 0.286 kg

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6. Instead of using kinematics, if you use dynamics (Newton's second law), the acceleration of the masses in the Atwood's machine can be calculated as: @= where m is the hanging mass, M is the mass of the system (the red tool box), and g 9.80 m/s² is the acceleration due to gravity. What is the system mass M when a 0.33 m/s² and the hanging mass is m 0.020 kg? M mg -0.400 kg M= 0.660 kg M 0.380 kg M = 0.574 kg M = 0.286 kg
Transcribed Image Text:6. Instead of using kinematics, if you use dynamics (Newton's second law), the acceleration of the masses in the Atwood's machine can be calculated as: @= where m is the hanging mass, M is the mass of the system (the red tool box), and g 9.80 m/s² is the acceleration due to gravity. What is the system mass M when a 0.33 m/s² and the hanging mass is m 0.020 kg? M mg -0.400 kg M= 0.660 kg M 0.380 kg M = 0.574 kg M = 0.286 kg
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