4.True or False? Prove your answer!a) Supposeh:R→R is not one-to-one, and suppose a, b ∈R with a != b. Then h(a) = h(b).The claim is.Proof of answer:b) Supposeg:R→R is a function such that for every x∈R, there exists y∈R such that g(x) != y. Then g is not onto.
4.True or False? Prove your answer!a) Supposeh:R→R is not one-to-one, and suppose a, b ∈R with a != b. Then h(a) = h(b).The claim is.Proof of answer:b) Supposeg:R→R is a function such that for every x∈R, there exists y∈R such that g(x) != y. Then g is not onto.
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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- 4.True or False? Prove your answer!a) Supposeh:R→R is not one-to-one, and suppose a, b ∈R with a != b. Then h(a) = h(b).The claim is.Proof of answer:b) Supposeg:R→R is a function such that for every x∈R, there exists y∈R such that g(x) != y. Then g is not onto.The claim is. Proof of answer:
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