4.5-10. In a college health fitness program, let X denote the weight in kilograms of a male freshman at the begin- ning of the program and Y denote his weight change during a semester. Assume that X and Y have a bivari- ate normal distribution with 4x = 72.30, a = 110.25, My = 2.80, o = 2.89, and p = -0.57. (The lighter stu- dents tend to gain weight, while the heavier students tend to lose weight.) Find (a) P(2.80 ≤ Y ≤ 5.35). (b) P(2.76 ≤ y ≤ 5.34| X= 82.3).
4.5-10. In a college health fitness program, let X denote the weight in kilograms of a male freshman at the begin- ning of the program and Y denote his weight change during a semester. Assume that X and Y have a bivari- ate normal distribution with 4x = 72.30, a = 110.25, My = 2.80, o = 2.89, and p = -0.57. (The lighter stu- dents tend to gain weight, while the heavier students tend to lose weight.) Find (a) P(2.80 ≤ Y ≤ 5.35). (b) P(2.76 ≤ y ≤ 5.34| X= 82.3).
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![4.5-10. In a college health fitness program, let X denote
the weight in kilograms of a male freshman at the begin-
ning of the program and Y denote his weight change
during a semester. Assume that X and Y have a bivari-
ate normal distribution with x = 72.30, o = 110.25,
My = 2.80, o = 2.89, and p = -0.57. (The lighter stu-
dents tend to gain weight, while the heavier students tend
to lose weight.) Find
(a) P(2.80 ≤ y ≤ 5.35).
(b) P(2.76 ≤ y ≤ 5.34 | X = 82.3).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2b62c17d-5c05-48d6-ac2b-a3a7c31907f7%2F9087ef60-8a21-4833-8ea7-7f63177f8aa7%2Foz5sjs2_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4.5-10. In a college health fitness program, let X denote
the weight in kilograms of a male freshman at the begin-
ning of the program and Y denote his weight change
during a semester. Assume that X and Y have a bivari-
ate normal distribution with x = 72.30, o = 110.25,
My = 2.80, o = 2.89, and p = -0.57. (The lighter stu-
dents tend to gain weight, while the heavier students tend
to lose weight.) Find
(a) P(2.80 ≤ y ≤ 5.35).
(b) P(2.76 ≤ y ≤ 5.34 | X = 82.3).
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