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4.3-3 Solve the following linear system, using four-decimal floating arithmetic, once with the first equation as pivotal equation and once with the second equation as pivotal equation, and finally with total pivoting. 0.1410 · 10-2x, + 0.4004 · 10-x, = 0.1142 · 10-' 0.2000 · 10°x, + 0.4912 · 10'x, = 0.1428 · 10' Compare with the exact answer x, = 1.000, x, = 0.2500.

4.3-3 Solve the following linear system, using four-decimal floating arithmetic, once with the first equation as pivotal equation and once with the second equation as pivotal equation, and finally with total pivoting. 0.1410 · 10-2x, + 0.4004 · 10-x, = 0.1142 · 10-' 0.2000 · 10°x, + 0.4912 · 10'x, = 0.1428 · 10' Compare with the exact answer x, = 1.000, x, = 0.2500.

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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4.3-3 Solve the following linear system, using four-decimal floating arithmetic, once with the first equation as pivotal equation and once with the second equation as pivotal equation, and finally with total pivoting. 0.1410 · 10-2x, + 0.4004 · 10-x, = 0.1142 · 10-1 0.2000 · 10°x, + 0.4912 · 10'x, = 0.1428 · 10' %3D Compare with the exact answer x, = 1.000, x, = 0.2500.
Transcribed Image Text:4.3-3 Solve the following linear system, using four-decimal floating arithmetic, once with the first equation as pivotal equation and once with the second equation as pivotal equation, and finally with total pivoting. 0.1410 · 10-2x, + 0.4004 · 10-x, = 0.1142 · 10-1 0.2000 · 10°x, + 0.4912 · 10'x, = 0.1428 · 10' %3D Compare with the exact answer x, = 1.000, x, = 0.2500.
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