2 The solution to the equation 4 7 has the following intermediate step: Зx-1 5х-3 1-3х . 10x-6+12x-4 =-35x+21. . 10x-6+12x-4=35x+21. . 10x-6+12x-4=35x– 21. b. 10x+6+12x – 4=-35x+21. d. 10x-6+12x-5=-35x+21.
2 The solution to the equation 4 7 has the following intermediate step: Зx-1 5х-3 1-3х . 10x-6+12x-4 =-35x+21. . 10x-6+12x-4=35x+21. . 10x-6+12x-4=35x– 21. b. 10x+6+12x – 4=-35x+21. d. 10x-6+12x-5=-35x+21.
Algebra: Structure And Method, Book 1
(REV)00th Edition
ISBN:9780395977224
Author:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Publisher:Richard G. Brown, Mary P. Dolciani, Robert H. Sorgenfrey, William L. Cole
Chapter2: Working With Real Numbers
Section2.7: Problem Solving: Consecutive Integers
Problem 3OE
Related questions
Question
![The solution to the equation
2 . 4
7
has the following intermediate step:
Зх-1 5х-3
1-3х
a. 10x – 6+12x – 4 =-35x+21.
c. 10x –6+12x-4= 35x+21.
e. 10х-6+12х—4%3 35х-21.
b. 10x+6+12x-4 =-35x+21.
d. 10x -6+12х-5 %3 -35х +21.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc1852b32-ef30-4f70-9b86-21fd75b4562c%2F5f5f61c0-d09d-4500-a3b1-c8f1096f6ad5%2Fueu4cif_processed.png&w=3840&q=75)
Transcribed Image Text:The solution to the equation
2 . 4
7
has the following intermediate step:
Зх-1 5х-3
1-3х
a. 10x – 6+12x – 4 =-35x+21.
c. 10x –6+12x-4= 35x+21.
e. 10х-6+12х—4%3 35х-21.
b. 10x+6+12x-4 =-35x+21.
d. 10x -6+12х-5 %3 -35х +21.
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