4.0 A force F(x) = N acts on a particle as it moves along the positive x-axis. (a) How much work (in J) does the force do on the particle as it moves from x = 2.5 m to x = 5.2 m? 2.93 (b) Picking a convenient reference point of the potential energy to be zero at x = 1 m, find the potential energy for this force. (Use the following as necessary: x. Assume U(x) is in joules an x is in meters. Do not include units in your answer.) U(x) = -2.93
4.0 A force F(x) = N acts on a particle as it moves along the positive x-axis. (a) How much work (in J) does the force do on the particle as it moves from x = 2.5 m to x = 5.2 m? 2.93 (b) Picking a convenient reference point of the potential energy to be zero at x = 1 m, find the potential energy for this force. (Use the following as necessary: x. Assume U(x) is in joules an x is in meters. Do not include units in your answer.) U(x) = -2.93
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![A force \( F(x) = \left( \frac{4.0}{x} \right) \) N acts on a particle as it moves along the positive x-axis.
(a) How much work (in J) does the force do on the particle as it moves from \( x = 2.5 \) m to \( x = 5.2 \) m?
- Answer: \( 2.93 \) J (correct)
(b) Picking a convenient reference point of the potential energy to be zero at \( x = 1 \) m, find the potential energy for this force. (Use the following as necessary: \( x \). Assume \( U(x) \) is in joules and \( x \) is in meters. Do not include units in your answer.)
- Answer: \( -2.93 \) (incorrect)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd52694c2-08a6-4e13-96ed-a87f03e48e22%2F601e3a44-401a-425c-a78d-1cf2f626c7f0%2F0jhtjzi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:A force \( F(x) = \left( \frac{4.0}{x} \right) \) N acts on a particle as it moves along the positive x-axis.
(a) How much work (in J) does the force do on the particle as it moves from \( x = 2.5 \) m to \( x = 5.2 \) m?
- Answer: \( 2.93 \) J (correct)
(b) Picking a convenient reference point of the potential energy to be zero at \( x = 1 \) m, find the potential energy for this force. (Use the following as necessary: \( x \). Assume \( U(x) \) is in joules and \( x \) is in meters. Do not include units in your answer.)
- Answer: \( -2.93 \) (incorrect)
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