: The force F = (6.71 N) î + (4.62 N) ĵ acts on a particle as it moves along a straight line from its initial position at to its final position at Ti = (2.59 m) î + (2.69 m) ĵ Ã = (8.58 m) î + (8.89 m) ĵ ▷ What is the work, in joules, done by the force on the particle? W= 93.69 J
: The force F = (6.71 N) î + (4.62 N) ĵ acts on a particle as it moves along a straight line from its initial position at to its final position at Ti = (2.59 m) î + (2.69 m) ĵ Ã = (8.58 m) î + (8.89 m) ĵ ▷ What is the work, in joules, done by the force on the particle? W= 93.69 J
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Force Acting on a Particle**
The force \( \vec{F} = (6.71 \, \text{N}) \, \hat{i} + (4.62 \, \text{N}) \, \hat{j} \) acts on a particle as it moves along a straight line. The particle transitions from its initial position \( \vec{r}_i = (2.59 \, \text{m}) \, \hat{i} + (2.69 \, \text{m}) \, \hat{j} \) to its final position \( \vec{r}_f = (8.58 \, \text{m}) \, \hat{i} + (8.89 \, \text{m}) \, \hat{j} \).
**Question:**
What is the work, in joules, done by the force on the particle?
**Solution:**
\( W = 93.69 \, \text{J} \)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F2dbe910a-0548-4393-97e4-b2099f203113%2Fd9ae62d8-6ee3-4a8f-9610-b22cfacb3114%2F19yuyl8_processed.png&w=3840&q=75)
Transcribed Image Text:**Force Acting on a Particle**
The force \( \vec{F} = (6.71 \, \text{N}) \, \hat{i} + (4.62 \, \text{N}) \, \hat{j} \) acts on a particle as it moves along a straight line. The particle transitions from its initial position \( \vec{r}_i = (2.59 \, \text{m}) \, \hat{i} + (2.69 \, \text{m}) \, \hat{j} \) to its final position \( \vec{r}_f = (8.58 \, \text{m}) \, \hat{i} + (8.89 \, \text{m}) \, \hat{j} \).
**Question:**
What is the work, in joules, done by the force on the particle?
**Solution:**
\( W = 93.69 \, \text{J} \)
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