4. Write the recurrence relation for the reverse(L) function: append(x, L) { Node curr = L; while(curr != null && curr.next != null) { curr - curr.next; } curr.next = x; (} reverse(L){ if(L == null) { return null; } else { Node front = L; Node rest - L.next; L.next = null; Node restReversed reverse(rest); append (font, restReversed); }

Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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4. Write the recurrence relation for the reverse(L) function:
append (x, L) {
Node curr =
L;
while(curr != null && curr.next != null) {
curr = curr.next;
}
curr.next = x;
}
reverse(L){
if(L
null) {
==
return null;
}
else {
Node front
L;
Node rest = L.next;
L.next
null;
Node restReversed
reverse(rest);
append (font, restReversed);
}
}
Transcribed Image Text:4. Write the recurrence relation for the reverse(L) function: append (x, L) { Node curr = L; while(curr != null && curr.next != null) { curr = curr.next; } curr.next = x; } reverse(L){ if(L null) { == return null; } else { Node front L; Node rest = L.next; L.next null; Node restReversed reverse(rest); append (font, restReversed); } }
Expert Solution
Step 1

This is the recurrence relation for reversing a linked list.

reverse(L)

{

if(L==null){

return null;

}

else{

Node front=L;

Node rest=L.next;

L.next=null;

Node restReveresed=reverse(rest)

append(front,restReveresed)

}

}

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