4. What was the molarity of a volumetric solution of disodium edetate if 28.50 mL of the solution were consumed by 185 mg of calcium carbonate? (MW CaCO3 = 100.09 g/mole) A. 0.04 M B. 0.05 M C. 0.06 M D. 0.07 M E. None of the choices 5. Calculate the weight necessary to prepare 1L of 0.05 N Potassium Permanganate (MW: 158.034 g/mol). A. 1.58 g B. 3.16 g C. 3.95 g D. 7.90 g E. None of the choices

4. What was the molarity of a volumetric solution of disodium edetate if 28.50 mL of the solution were consumed by 185 mg of calcium carbonate? (MW CaCO3 = 100.09 g/mole) A. 0.04 M B. 0.05 M C. 0.06 M D. 0.07 M E. None of the choices 5. Calculate the weight necessary to prepare 1L of 0.05 N Potassium Permanganate (MW: 158.034 g/mol). A. 1.58 g B. 3.16 g C. 3.95 g D. 7.90 g E. None of the choices

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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