4. Three roads are to be connected by a reversed curve. Road 1 has a length of 57.6 m.bearing due east, Road 2 has a length of 91.5 bearing N68°E, and Road 3 has a length of109.2 bearing S48°E. Find the length of the common radius of the new centerline of thethree roads (the common radius of the reversed curve)

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Answered: 4. Three roads are to be connected by a…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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A simple curve of the proposed extension of Mantabahadra Highway have a direction of tangent AB which is due north and tangent BC bearing N45°E. Point A is at the P.C. who stationing is 20 + 130.46. The degree of the curve is 4º. 1.1. Compute the long chord of the curve 1.2. Compute the stationing at point D on the curve along a line joining the center of the curve which makes an angle of 54° with the tangent line passing thru the P.C. 1.3. What is the length of the line from D to the intersection of the tangent AB.
Three roads are to be connected by a reversed curve. Road 1 has a length of 57.6 m. bearing due east, Road 2 has a length of 91.5 bearing N680E, and Road 3 has a length of 109.2 bearing S480E. Find the length of the common radius of the new centerline of the three roads (the common radius of the reversed curve) Show the illustration:
1. Two tangents intersecting at V with azimuths of 255°12' and 281°24 respectively are joined by a 4° simple curve. Without changing the direction of the two tangents, it is required to shorten the curve to one-fourth of the original length of the curve from the beginning of the curve. The stationing of the vertex of the new curve is at 10+545. Determine the following a. The radius of the original curve. b. Length of the original curve. c. Length of the new curve. d. Radius of the new curve. e. Tangent of the new curve. f. Stationing of the beginning of the curve. g. Stationing of the end of the curve. h. Long chord of the new curve.
5. The common tangent of a certain compound curve is parallel to its long chord. Its 546m long chord makes an angle of 19° and 13° with the shorter and longer tangents, respectively. Determine the length (m) of the compound curve. *
A 5° curve starts at station (5+432). The back and forward tangents of the curve have azimuths 260°40' and 294°37' respectively. A railroad AB intersects the curve at B. Line AB has azimuth 355°35'. Point A is 25 m from the point of intersection along the back tangent. At what stationing is the intersection of the railroad and the curve?
A horizontal curve is designed with a radius of 610 m. The curve has a tangent of 120 m and PI is at a station 3+140. Determine the stationing of the BC and EC.
The common tangent AB of a compound curve makes an angle with the tangents of the compound curve of 28° and 36° respectively. The stationing of V is 12+434.63. The degree of the first and second curve are 5.6° and 3.6° respectively. It is desired to substitute a simple curve that shall be tangent on the two tangent lines as well as the common tangent. Determine the following: ma) Radius of the simple curve b) stationing of new PC c) stationing of new PT
2. Two parallel tangents 20m apart are to be connected by a reversed curve. The radius of the first curve at the PC has a radius of 800m and the total length of the chord from the PC to PT is 300m. Stationing of the PC is 10 + 620. a. Find the central angle of each curve b. Find the radius of the curve passing thru the PT.
A compound curve connects three tangents having an azimuth of 240°, 270° and 280° respectively. The length of the chord is 382.3 m long measured from the PC to the PT of the curve and is parallel to the common tangent having an azimuth of 270°. If the stationing of the PT is 6 + 382.3 . a. Determine the total length of the compound curve. b. Determine the stationing of the PCC. c. Determine the stationing of the PC.
XIV. Compound Curve The given elements for the compound curves are the following: I1 = 35 degrees D1 = 5.6 degrees 12 = 55 degrees D2 = 8 degrees DC XV. Reverse Curve R1 35 T1 R1 35 55 L1 Determine the 1) R1, R2, 2) T1, T2, 3) L1, and L2. L2 R2 55 T2 DT
PROBLEM 21: Two parallel roads 300 m apart were connected by two equal simple curves and form a reverse curve. If the length of the intermediate tangent located between the two simple curves is 360 m and the two curves have equal radi of radii of 1200 m, find the central angle common to the two simple curves. a. 20°34'09" b. 18°06'24" c. 23°76'52" d. 21°33'03"
A reversed curve is connecting the two tangent lines AB and CD having directions of due East and D 60° E, respectively. The radius of the first curve at A (PC) is 200 m and that of the second curve at D (PT) is 400 m. Stationing of A (PC) is at 10 + 120.50. If ED is 300 m long and has a bearing of S 20° E. 1. Find the central angle of first curve 2. Find the central angle of the second curve 3. Find the stationing of PT

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