4. The failure envelope for drained peak (intact) strength ofa highly overconsolidated clay exhibits pronounced curvaturein the low effective normal stress range. For this reason intactstrength is defined using different values of intercept and angleof failure envelope for each range of effective normal stresso. An intact specimen of this clay is consolidated under anequal all-around pressure of 50 kPa and then axial stress isincreased under drained conditions until the maximum principalstress difference of 135 kPa is reached. Compute: (a) angle ofthe Mohr-Coulomb failure envelope for this stress condition,assuming an intercept of 10 kPa; (b) drained shear strengthon' the failure surface of the specimen, defined by the Mohr-Coulomb failure criterion; (c) drained shear strength of a nor-mally consolidated specimen of the same clay composition, ona failure surface with the same effective normal stress as inpart (b) on the assumption that the angle of internal friction o'is 20°; (d) fully softened shear strength of the intact specimen,on a failure surface with an effective normal stress as in part(b); and (e) residual shear strength on a preexisting shear surfaceof the overconsolidated clay, with an effective normal stress asin part (b) and for a residual friction angle o, equal to 10°.

Answered: Image /qna-images/answer/aef91bdc-0709-405c-9f58-a04336f89c25.jpg

4. The envelope highly overconsolidated clay exhibits pronounced curvature a the low effective normal stress range. For this reason intact trength is defined using different values of intercept and angle of failure envelope for each range of effective normal stress An intact specimen of this clay is consolidated under an equal all-around pressure of 50 kPa and then axial stress is ncreased under drained conditions until the maximum principal stress difference of 135 kPa is reached. Compute: (a) angle of long for this ndition

4. The envelope highly overconsolidated clay exhibits pronounced curvature a the low effective normal stress range. For this reason intact trength is defined using different values of intercept and angle of failure envelope for each range of effective normal stress An intact specimen of this clay is consolidated under an equal all-around pressure of 50 kPa and then axial stress is ncreased under drained conditions until the maximum principal stress difference of 135 kPa is reached. Compute: (a) angle of long for this ndition

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

a=1 b=5 c=5 d=0
Please help me solve
indicate the final answer in 3 decimal places.
Determine shear strength of clay having value of cohesion 31 KPa Normal stress 100 KPa and angle of internal is 31 degree
Problem-(5) In a triaxial compression test, the major principal stress was 90 kPa and the minor principal stress was 30 kPa, at failure. The pore pressure at failure was observed to be 10kPa. Find the tangent of the angle of shearing resistance of the sandy soil.
Q: A consolidated-drained tri-axial test was conducted on a normally consolidated clay. The results are as following: confining stress, G3 = 150 kN/m² and deviator stress, (Aod)t = 150 kN/m². i) Determine angle of friction, q; ii) Determine angle 0 that the failure plane makes with the major principal plane; iii) Find the normal stress and the shear stress ty on the failure plane; and iv) Determine the effective normal stress on the plane of maximum shear stress. Express your results in two decimal places.
Solve 6-1 using detailed steps
A sample of dry sand in relatively loose condi-tion is subject to a triaxial test. The sample failswhen the confining stress (minor principalstress) is 50 kPa and the axial stress (major prin-cipal stress) is 170 kPa. What is the angle ofinternal friction for the soil?
In a consolidated drained triaxial test, a specimen of clay tails at a cell pressure of 100KN/m?. The effective shear strength parameters are c' = 20KN/m? and o' = 300 Determine the major principal stress?. kN/m?
At one point in a soil mass, the minor principal stress is 74 kPa. What is the maximum value possible for the major principal stress at this point if the shear stress cannot exceed 64 kPa?
A consolidated-undrained test on a normally consolidate clay yield the following results: Confining Pressure 167 KPa; Deviator Stress = 184 KPa; Pore Pressure = 74 KPa. Calculate the normal stress at the failure plane at drained condition in KPa.