
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The given reaction is a Friedel - Crafts alkylation reaction.
In this reaction alkylation of aromatic ring takes place with the help of alkyl halide & using strong Lewis acid such as aluminum trichloride (AlCl3) as a catalyst.
This reaction proceed by electrophilic aromatic substitution mechanism.
In this reaction removal of -Cl from N-propyl chloride to form primary carbocation i.e, electrophile species. After rearrangement it convert into more stable carbocation secondary carbocation formed.
Double bond of aromatic ring attacks on this carbocation ,so aromaticity is break, & aromatic carbocation formed.Now, -(H+) on carbocation remove so, aromaticity is restored.
Now, H+ reacts with AlCl4- to give back HCl and AlCl3.
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