4. In a recent study conducted by Pulse Measurement Asia, their results show that a higher percentage of females have normal resting pulse rate compared with males. Dr. Castillejo, is interested to know whether this result also applies among gym members. Use the R commander output below to test Dr. Castillejo's claim. Write a brief report about the analysis by identifying the set of hypotheses to be tested, the appropriate test to use, and implications and recommendations of/from the conclusions. Note: The
4. In a recent study conducted by Pulse Measurement Asia, their results show that a higher percentage of females have normal resting pulse rate compared with males. Dr. Castillejo, is interested to know whether this result also applies among gym members. Use the R commander output below to test Dr. Castillejo's claim. Write a brief report about the analysis by identifying the set of hypotheses to be tested, the appropriate test to use, and implications and recommendations of/from the conclusions. Note: The
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question
![4. In a recent study conducted by Pulse Measurement Asia, their results show that a higher percentage of
females have normal resting pulse rate compared with males. Dr. Castillejo is interested to know whether
this result also applies among gym members. Use the R commander output below to test Dr. Castillejo's
claim. Write a brief report about the analysis by identifying the set of hypotheses to be tested, the
appropriate test to use, and implications and recommendations of/from the conclusions. Note: The
following R commander output defines the difference to be Female - Male.
R COMMANDER OUTPUT
2-sample test for equality of proportions with continuity correction
1.0088, df = 1, p-value = 0.3152
data: Table
X-squared
alternative hypothesis: twasided
95 percent confidence interval:
-0.1286700 0.4964861
mple estimates:
prop 1
prop 2
0.6666667 0.4827586
(5 points)
R COMMANDER OUTPUT
2-sample test for equality of proportions with continuity correction
data: Table
X-squared = 1.0088, df = 1, p-value = 0.8424
alternative hypothesis: less
95 percent confidence interval:
-1.0000000 0.4528317
sample estimates:
prop 1
prop 2
0.6666667 0.4827586
R COMMANDER OUTPUT
2-sample test for equality of proportions with continuity correction
data: Table
X-squared = 1.0088, df = 1, p-value = 0.1576
alternative hypothesis: greater
95 percent confidence interval:
-0.08501564 1.00000000
sample estimates:
prop 1 prop 2
0.6666667 0.4827586](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F537ffd5c-2b4b-4308-91aa-4c7110a55384%2Fe0c18877-aeba-4de8-9239-4f1728f285c4%2Fnfalzsn_processed.jpeg&w=3840&q=75)
Transcribed Image Text:4. In a recent study conducted by Pulse Measurement Asia, their results show that a higher percentage of
females have normal resting pulse rate compared with males. Dr. Castillejo is interested to know whether
this result also applies among gym members. Use the R commander output below to test Dr. Castillejo's
claim. Write a brief report about the analysis by identifying the set of hypotheses to be tested, the
appropriate test to use, and implications and recommendations of/from the conclusions. Note: The
following R commander output defines the difference to be Female - Male.
R COMMANDER OUTPUT
2-sample test for equality of proportions with continuity correction
1.0088, df = 1, p-value = 0.3152
data: Table
X-squared
alternative hypothesis: twasided
95 percent confidence interval:
-0.1286700 0.4964861
mple estimates:
prop 1
prop 2
0.6666667 0.4827586
(5 points)
R COMMANDER OUTPUT
2-sample test for equality of proportions with continuity correction
data: Table
X-squared = 1.0088, df = 1, p-value = 0.8424
alternative hypothesis: less
95 percent confidence interval:
-1.0000000 0.4528317
sample estimates:
prop 1
prop 2
0.6666667 0.4827586
R COMMANDER OUTPUT
2-sample test for equality of proportions with continuity correction
data: Table
X-squared = 1.0088, df = 1, p-value = 0.1576
alternative hypothesis: greater
95 percent confidence interval:
-0.08501564 1.00000000
sample estimates:
prop 1 prop 2
0.6666667 0.4827586
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