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4. If atmospheric pressure is 97.75kPa and the gage attached to the tank reads 188 mmHg vacuum, find the absolute pressure within the tank.

4. If atmospheric pressure is 97.75kPa and the gage attached to the tank reads 188 mmHg vacuum, find the absolute pressure within the tank.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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1. If the pressure at a point in the ocean is 75 kPa, what is the pressure 27 meters below this point? 2. If the pressure in the air space above an oil (s = 0.80) surface in a closed tank is 120 kPa absolute, what is the gage pressure 2 m below the surface? 3. Find the absolute pressure in kPa at a depth of 10 m below the free surface of Oil of sp. gr. 0.80 if the barometric reading is 760 mmHg. 4. If atmospheric pressure is 97.75kPa and the gage attached to the tank reads 188 mmHg vacuum, find the absolute pressure within the tank. 5. In the figure shown, if the atmospheric pressure is 101.03 kPa and the absolute at the bottom of the tank is 3 kPa, what is the specific gravity olive Oil? SAE Oil, s= 0.89 Water Olive, s= ?.. Mercury, s= 13.6 1.5 m + 2.5 m 2.9 m + 0.4 m
Transcribed Image Text:1. If the pressure at a point in the ocean is 75 kPa, what is the pressure 27 meters below this point? 2. If the pressure in the air space above an oil (s = 0.80) surface in a closed tank is 120 kPa absolute, what is the gage pressure 2 m below the surface? 3. Find the absolute pressure in kPa at a depth of 10 m below the free surface of Oil of sp. gr. 0.80 if the barometric reading is 760 mmHg. 4. If atmospheric pressure is 97.75kPa and the gage attached to the tank reads 188 mmHg vacuum, find the absolute pressure within the tank. 5. In the figure shown, if the atmospheric pressure is 101.03 kPa and the absolute at the bottom of the tank is 3 kPa, what is the specific gravity olive Oil? SAE Oil, s= 0.89 Water Olive, s= ?.. Mercury, s= 13.6 1.5 m + 2.5 m 2.9 m + 0.4 m
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