4. If a 32 foot chain is hanging (balanced) on a metal peg on a wall. At time t=0, with the chain initially at rest and hanging two feet below the equilibrium position as shown, the chain starts to slip. The position X at time t can be explained by the DE d²X 64 di² 32 -X=0 with initial conditions --- that X(0)=2 and X'(0)=0. (a) Show all work to solve the DE and find the function X(t) that describes the position of the chain below the equilibrium point. (b) Find the speed at which the chain is falling when it first leaves the peg (i.e., when X-16). Show work/calculator commands. You my use the nspire for any algebraic steps. equilibrium point

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4. If a 32 foot chain is hanging (balanced) on a metal peg on a wall.
At time t=0, with the chain initially at rest and hanging two feet below the
equilibrium position as shown, the chain starts to slip. The position X at
d² X
time t can be explained by the DE
64
32
X=0 with initial conditions
dt²
that X(0) = 2 and X'(0) = 0.
(a) Show all work to solve the DE and find the function X(t) that describes the
position of the chain below the equilibrium point.
(b) Find the speed at which the chain is falling when it first leaves the peg
(i.e., when X-16). Show work/calculator commands. You my use the nspire for any
algebraic steps.
equilibrium point
Transcribed Image Text:4. If a 32 foot chain is hanging (balanced) on a metal peg on a wall. At time t=0, with the chain initially at rest and hanging two feet below the equilibrium position as shown, the chain starts to slip. The position X at d² X time t can be explained by the DE 64 32 X=0 with initial conditions dt² that X(0) = 2 and X'(0) = 0. (a) Show all work to solve the DE and find the function X(t) that describes the position of the chain below the equilibrium point. (b) Find the speed at which the chain is falling when it first leaves the peg (i.e., when X-16). Show work/calculator commands. You my use the nspire for any algebraic steps. equilibrium point
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